代碼生成作爲{"error_message":null,"status":"InvalidRequest"}
輸出,其中我想獲得它作爲{"error_message":null,"status":"INVALID_REQUEST"}
如何基於屬性序列化與JSON.NET的枚舉?下面
所以簡單地說,我不知道如何兌現PropertyName
屬性,同時與JSON.NET序列化?
void Main()
{
var payload = new GooglePlacesPayload();
payload.Status = StatusCode.InvalidRequest;
JsonConvert.SerializeObject(payload).Dump();
}
public class GooglePlacesPayload
{
[JsonProperty(PropertyName = "error_message")]
public string ErrorMessage { get; set; }
[JsonProperty(PropertyName = "status")]
[JsonConverter(typeof(StringEnumConverter))]
public StatusCode Status { get; set; }
}
[Flags]
public enum StatusCode
{
// reference https://developers.google.com/maps/premium/previous-licenses/articles/usage-limits#limitexceeded
// reference https://developers.google.com/places/web-service/search#PlaceSearchStatusCodes
None = 0,
// indicates that no errors occurred; the place was successfully detected and at least one result was returned.
[JsonProperty(PropertyName = "OK")]
Ok = 1,
// indicates that the search was successful but returned no results. This may occur if the search was passed a latlng in a remote location.
[JsonProperty(PropertyName = "ZERO_RESULTS")]
ZeroResults = 2,
// indicates that you are over your quota. The daily quotas are reset at midnight, Pacific Time.
[JsonProperty(PropertyName = "OVER_QUERY_LIMIT")]
OverQueryLimit = 4,
// indicates that your request was denied, generally because of lack of an invalid key parameter.
[JsonProperty(PropertyName = "REQUEST_DENIED")]
RequestDenied = 8,
// generally indicates that a required query parameter (location or radius) is missing.
[JsonProperty(PropertyName = "INVALID_REQUEST")]
InvalidRequest = 16,
// When the Google Places service returns a status code other than OK, there may be an additional error_message field within the search response object.
// This field contains more detailed information about the reasons behind the given status code.
Positive = Ok | ZeroResults,
Negative = OverQueryLimit | RequestDenied | InvalidRequest
}
我假定你正在尋找*任何*的方式來改變枚舉的序列化。如果你正在尋找一種使用'PropertyName'的方法,隨時恢復並添加一個更新到你的問題。 –
你的假設是正確的。謝謝! – cilerler