在這臺服務器上找不到請求的URL /edit.php

Question

我剛纔在下面得到這個錯誤。它在localhost上工作。有任何想法嗎？ 任何有關如何谷歌這個錯誤的建議也會有很大幫助，因爲我不知道問題出在哪裏。

「在此服務器上找不到請求的URL /edit.php」。

<?php 
include ('includes/connection.php'); 
include ('includes/functions.php'); 
include ('includes/header.php'); 

$jobId = $_GET["id"]; 
$query = "SELECT * FROM Freight, WHERE id = '$jobId'"; 
$result = mysqli_query($connection, $query); 

if (mysqli_num_rows($result) > 0) { 
    while ($row = mysqli_fetch_assoc($result)) { 
     $jobArrival   = $row["Arrival"]; 
     $jobDeparture   = $row["Departure"]; 
     $jobClient    = $row["Client"]; 
     $jobAirportOfDeparture = $row["AirportOfDeparture"]; 
     $jobAirportOfArrival = $row["AirportOfArrival"]; 
     $jobAdditionalInfo  = $row["AdditionalInfo"]; 
     $jobBoxType   = $row["BoxType"]; 
     $jobTemp    = $row["Temp"]; 

     // prideti is dezes table 
     // $pavadinimas   = $row["pavadinimas"]; 
     // $likutis    = $row["likutis"]; 

     if (isset($_POST['update'])) { 
      $jobArrival   = validateFormData($_POST['jobArrival']); 
      $jobDeparture   = validateFormData($_POST['jobDeparture']); 
      $jobClient    = validateFormData($_POST['jobClient']); 
      $jobAirportOfDeparture = validateFormData($_POST['jobAirportOfDeparture']); 
      $jobAirportOfArrival = validateFormData($_POST['jobAirportOfArrival']); 
      $jobAdditionalInfo  = validateFormData($_POST['jobAdditionalInfo']); 
      $jobBoxType   = validateFormData($_POST['jobBoxType']); 
      $jobTemp    = validateFormData($_POST['jobTemp']); 
      $query     = "UPDATE Freight SET Arrival   = '$jobArrival', 
                 Departure   = '$jobDeparture', 
                 Client    = '$jobClient', 
                 AirportOfDeparture = '$jobAirportOfDeparture', 
                 AirportOfArrival = '$jobAirportOfArrival', 
                 AdditionalInfo  = '$jobAdditionalInfo', 
                 BoxType   = '$jobBoxType', 
                 Temp    = '$jobTemp' 
                WHERE id = '$jobId'"; 
      $result = mysqli_query($connection, $query); 
      if ($result) { 
       header("Location: formdisplay.php"); 
      } else { 
       "Klaida" . mysqli_error($connection); 
      } 
     } 
    } 
} 
else { 
    echo "Nera irasu!!!!!!!!!!!!!!"; 
} 

if (isset($_POST['istrinti'])) { 
    $query = "DELETE FROM Freight WHERE id ='$jobId'"; 
    $result = mysqli_query($connection, $query); 
    if ($result) { 
     header("Location: formdisplay.php?alert=deleted"); 
    } 
    else { 
     echo "Error" . mysqli_error($connection); 
    } 
} 

mysqli_close($connection); 
?> 

<h1> Iraso koregavimas</h1> 
<table> 
    <tr> 
     <td>Arrival</td> 
     <td>Departure</td> 
     <td>Client</td> 
     <td>Airport Of Departure</td> 
     <td>Airport Of Arrival</td> 
     <td>Additional Info</td> 
     <td>Box Type</td> 
     <td>Temp</td> 
    </tr> 
    <tr> 
     <form method="POST" action="<?php echo htmlspecialchars($_SERVER['PHP_SELF']); ?>?id=<?php echo $jobId; ?>"> 
      <td> 
       <input type = "text" 
         value = "<?php echo $jobArrival ?>" 
         name = "jobArrival"> 
      </td> 
      <td> 
       <input type = "text" 
         value = "<?php echo $jobDeparture ?>" 
         name = "jobDeparture"> 
      </td> 
      <td> 
       <input type = "text" 
         value = "<?php echo $jobClient ?>" 
         name = "jobClient"> 
      </td> 
      <td> 
       <input type = "text" 
         value = "<?php echo $jobAirportOfDeparture ?>" 
         name = "jobAirportOfDeparture"> 
      </td> 
      <td> 
       <input type = "text" 
         value = "<?php echo $jobAirportOfArrival ?>" 
         name = "jobAirportOfArrival"> 
      </td> 
      <td> 
       <input type = "text" 
         value = "<?php echo $jobAdditionalInfo ?>" 
         name = "jobAdditionalInfo"> 
      </td> 
      <td> 
       <input type = "text" 
         value = "<?php echo $jobBoxType ?>" 
         name = "jobBoxType"> 
      </td> 
      <td> 
       <input type = "text" 
         value = "<?php echo $jobTemp ?>" 
         name = "jobTemp"> 
      </td> 
      <td> 
       <input type = "submit" 
         name = "update" 
         value = "update" 
         href = "formdisplay.php"></td> 
      <td> 
       <input type ="submit" 
         name ="istrinti" 
         value ="istrinti" 
         href ="formdisplay.php"> 
      </td> 
     </form> 
    </tr> 
</table> 

Answer 1

這裏的關鍵很可能在​​的/。嘗試僅包括edit.php，或者更直接地將它路徑到目錄。

祝你好運！

Answer 2

問題已解決。第143行的問題，很少有錯誤的空間。 花了我一個星期才找到它:) 代碼看起來像這樣<form method="POST" action="<?php echo htmlspecialchars($_SERVER['PHP_SELF']); ?>?id=<?php echo $jobId ?>">