2012-07-20 82 views
0

我想製作一個簡單的網絡應用程序,可以上傳文件並將文件提供給python腳本。燒瓶似乎適合這種用途。用戶然後可以從腳本下載文件輸出。請讓我知道如何解析python腳本中的文件並獲取輸出。到目前爲止,我能夠做到這上傳文件的情況如下:蟒蛇程序的網絡界面:上傳和下載文件

from flask import Flask 
from flask import request 
app = Flask(__name__) 

def allowed_file(filename): 
    return '.' in filename and \ 
     filename.rsplit('.', 1)[1] in ALLOWED_EXTENSIONS 

@app.route('/', methods=['GET', 'POST']) 
def upload_file(): 
    if request.method == 'POST': 
     file = request.files['file'] 
     if file and allowed_file(file.filename): 
      filename = secure_filename(file.filename) 
      file.save(os.path.join(app.config['UPLOAD_FOLDER'], filename)) 
      return redirect(url_for('uploaded_file', 
         filename=filename)) 
    return ''' 
<!doctype html> 
<title>Upload new File</title> 
<h1>Upload new File</h1> 
<form action="" method=post enctype=multipart/form-data> 
<p><input type=file name=file> 
<input type=submit value=Upload> 
</form 
''' 
app.run() 

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