我正在開發一個HTML/PHP的商店網站,爲了讓人們檢查他們想要購買的物品,我在每個產品中放置了一個複選框,名稱爲「Order_(產品)」。事情是,當我需要檢查該複選框是否被選中時,它永遠不會。我不確定我做錯了什麼。下面的代碼生成的複選框:PHP複選框與變量名稱從未檢查
while ($i < $num_linhas) {
$row = pg_fetch_row($result, $i);
echo "<div class='product'>
<h3>".$row[2]."</h3>
<img src='common/images/".$tipo_produto."/".$row[1].".jpg' alt='".$row[1]."'>
<br>";
if($_SESSION['tipo'] == "cliente")
{
echo '<form method="POST"><input type="checkbox" name="encomendar_'.$row[0].'"></form>Encomendar';
}
$i++;
echo "</div>";
}
和代碼來檢查,如果他們被選中(不同的腳本):
while($i < $num_linhas)
{
$row = pg_fetch_row($result_1, $i);
if(isset($_POST['encomendar_'.$row[0].'']))
{
echo $row[0];
$query = "SELECT * from biofood.encomenda";
$result_2 = pg_exec($conn, $query);
$num_linhas = pg_num_rows($result_2);
$j = $num_linhas + 1;
$t = time();
$data = date('y-m-d');
$hour = date('H:i');
$id_cliente = $_SESSION['id'];
$query = "Insert into biofood.encomenda(id,data,hora,id_cliente,id_produto,estado) VALUES('".$j."','".$data."','".$hour."','".$id_cliente."','".$row[0]."','Não tratada')";
$result_3 = pg_exec($conn, $query);
}
$i++;
}
檢查http://stackoverflow.com/questions/4997252/get-post-from-multiple-checkboxes出來的更容易的工作方式.. – Naruto