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我是春季安全新手。在春季安全中頁面不根據基於intercept-url
的角色進行渲染。 default-target-url
被渲染爲每個請求,不論角色的春季安全不顯示相應頁面
這是我的web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" version="2.5">
<display-name>bjgsecurity</display-name>
<!-- The front controller of this Spring Web application, responsible for handling all application requests -->
<servlet>
<servlet-name>mvc-dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<!-- Map all requests to the DispatcherServlet for handling -->
<servlet-mapping>
<servlet-name>mvc-dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<!-- needed for ContextLoaderListener -->
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>
/WEB-INF/mvc-dispatcher-servlet.xml,
/WEB-INF/security-config.xml
</param-value>
</context-param>
<!-- Bootstraps the root web application context before servlet initialization -->
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<filter>
<filter-name>springSecurityFilterChain</filter-name>
<filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
</filter>
<filter-mapping>
<filter-name>springSecurityFilterChain</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
</web-app>
這是安全-config.xml中
<beans:beans xmlns="http://www.springframework.org/schema/security"
xmlns:beans="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/security
http://www.springframework.org/schema/security/spring-security-3.2.xsd">
<http auto-config="true">
<access-denied-handler error-page="/403page" />
<intercept-url pattern="/admin**" access="ROLE_ADMIN"/>
<intercept-url pattern="/user**" access="ROLE_USER"/>
<form-login login-page='/login' username-parameter="username"
password-parameter="password" default-target-url="/user"
authentication-failure-url="/login?authfailed" />
<logout logout-success-url="/login?logout" />
</http>
<!-- <authentication-manager> <authentication-provider> <user-service> <user
name="user" password="[email protected]" authorities="ROLE_ADMIN" /> </user-service>
</authentication-provider> </authentication-manager> -->
<authentication-manager>
<authentication-provider>
<jdbc-user-service data-source-ref="dataSource"
users-by-username-query="select username,password, enabled from users where username=?"
authorities-by-username-query="select username, role from user_roles where username =? " />
</authentication-provider>
</authentication-manager>
</beans:beans>
這是我的控制器
package com.model.controller;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestParam;
import org.springframework.web.servlet.ModelAndView;
@Controller
public class LoginController
{
@RequestMapping("login")
public ModelAndView getLoginForm(@RequestParam(required=false) String authfailed, String logout, String denied)
{
String message="";
if(authfailed != null)
{
message="invalid username of password. plz try again!";
}
else if (logout != null) {
message="Loged Out Successfully.. login again to continue !";
}
else if (denied != null) {
message = "Access denied for this user !";
}
return new ModelAndView("login", "message", message);
}
@RequestMapping("user")
public String getUserPage()
{
return "user";
}
@RequestMapping("admin")
public String getAdminPage() {
return "admin";
}
@RequestMapping("403page")
public String get403denied() {
return "redirect:login?denied";
}
}
我的代碼有什麼問題
添加/(斜槓),但它並沒有幫助。它只採取默認目標網址,但它不是基於攔截 - url –
渲染請任何人提前告知我在此先感謝 –
已更新我的答案..它可能會幫助你...如果不在這兩個地方做一些研發..將幫助你:) –