如何使用MySQL獲取最近的日期

Question

如何使用MySQL獲取最近的日期？我嘗試了max，但沒有得到我想要的結果。我的表看起來像這樣：

+---------+---------+-----------------------+--------+------------+---------+ 
| Name | idStore | Name     | idItem | date  | price | 
+---------+---------+-----------------------+--------+------------+---------+ 
| walmart |  1 | Red Delicious Apples |  1 | 2011-10-22 | 0.98000 | 
| walmart |  1 | Red Delicious Apples |  1 | 2011-10-28 | 0.98000 | 
| walmart |  1 | Red Delicious Apples |  1 | 2011-10-28 | 0.98000 | 
| walmart |  1 | Red Delicious Apples |  1 | 2011-11-22 | 0.98000 | 
| walmart |  1 | Honeycrisp Apples  |  2 | 2011-10-22 | 1.98000 | 
| walmart |  1 | Sonya Apples   |  3 | 2011-10-22 | 2.88000 | 
| walmart |  1 | Gold Delicious Apples |  4 | 2011-10-22 | 0.98000 | 
| walmart |  1 | Sweet Tango Apples |  5 | 2011-10-22 | 2.48000 | 
| walmart |  1 | Granny Smith Apples |  6 | 2011-10-22 | 1.28000 | 
| walmart |  1 | Fugi Apples   |  7 | 2011-10-22 | 1.38000 | 
+---------+---------+-----------------------+--------+------------+---------+ 

我想這個表：

+---------+---------+-----------------------+--------+------------+---------+ 
| Name | idStore | Name     | idItem | date  | price | 
+---------+---------+-----------------------+--------+------------+---------+ 
| walmart |  1 | Red Delicious Apples |  1 | 2011-11-22 | 0.98000 | 
| walmart |  1 | Honeycrisp Apples  |  2 | 2011-10-22 | 1.98000 | 
| walmart |  1 | Sonya Apples   |  3 | 2011-10-22 | 2.88000 | 
| walmart |  1 | Gold Delicious Apples |  4 | 2011-10-22 | 0.98000 | 
| walmart |  1 | Sweet Tango Apples |  5 | 2011-10-22 | 2.48000 | 
| walmart |  1 | Granny Smith Apples |  6 | 2011-10-22 | 1.28000 | 
| walmart |  1 | Fugi Apples   |  7 | 2011-10-22 | 1.38000 | 
+---------+---------+-----------------------+--------+------------+---------+ 

我有很難搞清楚了這一點。謝謝！

Answer 1

在線實例查詢

http://data.stackexchange.com/stackoverflow/q/118881/how-can-i-get-the-most-resent-date-using-mysql

SELECT NameStore, idStore, Name, idItem, max(date) AS date, price 
FROM tablename 
GROUP by NameStore, idStore, Name, idItem, price 
ORDER BY date DESC, idItem ASC 

Answer 2

把這個末ORDER BY date DESC

因此，使它看起來像這樣：

SELECT * FROM `tablename` ORDER BY `date` DESC 

在上面的SQL語句使用DISTINCT(Name)或GROUP BY Name，就會使一個項目彈出一次。

Answer 3

您可以通過使用組：

select NameStore, idStore, Name, idItem, max(date) date, price 
from table 
group by NameStore, idStore, Name, idItem, price 

Answer 4

您必須使用GROUP BY條款是這樣的：

SELECT Name, idStore, Name, idItem, date, price 
FROM mytable 
GROUP BY idItem 
ORDER BY date DESC, idItem DESC; 

更改使用DESC或ASC順序方向。您可以通過閱讀文檔瞭解更多信息。

Answer 5

見SQL Select only rows with Max Value on a Column

SELECT yt1.* 
FROM yourtable yt1 
LEFT OUTER JOIN yourtable yt2 ON (yt1.idItem = yt2.idItem AND yt1.date < yt2.date) 
WHERE yt2.idItem IS NULL;