我創建了搜索輸入來搜索列表中的一些項目。我想,如果項搜索不在列表內顯示添加按鈕像html代碼:如何在AngularJS的列表中找不到輸入值時顯示元素?
<div ng-controller="foodCtrl">
<form>
<div class="form-group row foodGroupp" >
<label for="inputFood" class="col-sm-2 col-form-label">food</label>
<div class="col-sm-10">
<input type="text" class="form-control" id="inputFood" ng-model="inputFood" placeholder="Write some food" ng-keyup="doCheck()">
</div>
<span id="addIcon" ng-show="showIcon">
<button class="btn btn-default">+</button>
</span>
<ul ng-show="inputFood" id="foodList">
<li ng-repeat="foodN in foodName | filter : inputFood">
<span>{{ foodN.name}}</span>
</li>
</ul>
</div>
<div class="form-group row">
<div class="offset-sm-2 col-sm-10">
<button type="submit" class="btn btn-primary">הוסף</button>
</div>
</div>
</form>
</div>
的JavaScript代碼如下所示:
var app = angular.module('mainApp', []);
app.controller('foodCtrl',function($scope,$http){
$scope.foods = [];
$scope.foodName = [];
$http.get('/files/foodName.json')
.success(function(response){
$scope.foodName = response;
});
$scope.showIcon = false;
$scope.doCheck = function(){
$(function() {
if($scope.inputFood != ""){
var sizeOfList = $("#foodList").find("li").length;
if(sizeOfList == 0){
console.log("sizeOfList " +sizeOfList);
$scope.showIcon = true;
}
}else{
$scope.showIcon = false;
}
});
}
});
它不能正常工作。如果值的長度是1或列表顯示,它仍然顯示我的圖標。
它的作品!非常感謝。 – oded