您可以通過以下邏輯解決的問題:要添加
1)列的確定數量。
2)計算值列基礎的要求
data test;
input start end;
informat start date9. end date9.;
format start date9. end date9.;
datalines;
22-Jun-15 22-Oct-15
09-Jan-15 15-May-15
;
run;
/*******Determining number of columns*******/
data noc_cal;
set test;
no_of_col = floor((end-start)/30);
run;
proc sql;
select max(no_of_col) into: number_of_columns from noc_cal;
run;
/*******Making an array where 1st iteration(tik1) is increased by 35days whereas others are incremented by 30days*******/
data test1;
set test;
array tik tik1-tik%sysfunc(COMPRESS(&number_of_columns.));
format tik: date9.;
tik1 = intnx('DAYS',START,35);
do i= 2 to %sysfunc(COMPRESS(&number_of_columns.));
tik[i]= intnx('DAYS',tik[i-1],30);
if tik[i] > end then tik[i]=.;
end;
drop i;
run;
替代方法(櫃面你不想使用PROC SQL)
data test;
input start end;
informat start date9. end date9.;
format start date9. end date9.;
datalines;
22-Jun-15 22-Oct-15
09-Jan-15 15-May-15
;
run;
/*******Determining number of columns*******/
data noc_cal;
set test;
no_of_col = floor((end-start)/30);
run;
proc sort data=noc_cal;
by no_of_col;
run;
data _null_;
set noc_cal;
by no_of_col;
if last.no_of_col;
call symputx('number_of_columns',no_of_col);
run;
/*******Making an array where 1st iteration(tik1) is increased by 35days whereas others are incremented by 30days*******/
data test1;
set test;
array tik tik1-tik%sysfunc(COMPRESS(&number_of_columns.));
format tik: date9.;
tik1 = intnx('DAYS',START,35);
do i= 2 to %sysfunc(COMPRESS(&number_of_columns.));
tik[i]= intnx('DAYS',tik[i-1],30);
if tik[i] > end then tik[i]=.;
end;
drop i;
run;
我的輸出:
> **start |end |tik1 | tik2 |tik3 |tik4**
> 22Jun2015 |22Oct2015 |27Jul2015| 26Aug2015|25Sep2015|
> 09Jan2015 |15May2015 |13Feb2015| 15Mar2015|14Apr2015|14May2015
你目前對這個問題的解決方法是什麼? –
你可以有一個宏來獲取列的值,並在循環中增加變量名....用你得到的變量創建一個臨時表......並且與之前的tabel合併 –
你真的想要寬輸出格式?或者一個長而窄的格式也可以工作,即爲每個時期生成一個記錄, – Quentin