如何在PowerShell中執行按位或（|）枚舉？

我想執行一個按位或（|）操作來應用多個枚舉到.NET程序集使用的PowerShell中的變量。但是，當單管字符做到這一點時，我得到一個Expressions are only allowed as the first element of a pipeline錯誤。如何在PowerShell中分配多個枚舉？如何在PowerShell中執行按位或（|）枚舉？

$everyone = New-Object System.Security.Principal.SecurityIdentifier([System.Security.Principal.WellKnownSidType]::WorldSid, $null); 
    $fsr = [System.Security.AccessControl.FileSystemRights]::Read; 
    $if = [System.Security.AccessControl.InheritanceFlags]::ContainerInherit | [System.Security.AccessControl.InheritanceFlags]::ObjectInherit; 
    $pf = [System.Security.AccessControl.PropagationFlags]::None; 
    $act = [System.Security.AccessControl.AccessControlType]::Allow; 
    $accessRule = New-Object System.Security.AccessControl.FileSystemAccessRule($everyone, $fsr, $if, $pf, $act);

來源

2015-01-20 Andrew Odri

使用-bor

[System.Security.AccessControl.InheritanceFlags]::ContainerInherit -bor [System.Security.AccessControl.InheritanceFlags]::ObjectInherit 

ContainerInherit, ObjectInherit

來源

2015-01-20 18:40:43

這是使用-bOr操作完成。請參閱TechNet documentation about ¾ down the page。

上面的代碼示例是這樣的-bOr後實施：

$everyone = New-Object System.Security.Principal.SecurityIdentifier([System.Security.Principal.WellKnownSidType]::WorldSid, $null); 
    $fsr = [System.Security.AccessControl.FileSystemRights]::Read; 
    $if = [System.Security.AccessControl.InheritanceFlags]::ContainerInherit -bOr [System.Security.AccessControl.InheritanceFlags]::ObjectInherit; 
    $pf = [System.Security.AccessControl.PropagationFlags]::None; 
    $act = [System.Security.AccessControl.AccessControlType]::Allow; 
    $accessRule = New-Object System.Security.AccessControl.FileSystemAccessRule($everyone, $fsr, $if, $pf, $act);

來源

2015-01-20 18:42:24

你也可以把兩個inheritanceflag對象的數組裏面：

$everyone = New-Object System.Security.Principal.SecurityIdentifier([System.Security.Principal.WellKnownSidType]::WorldSid, $null); 
$fsr = [System.Security.AccessControl.FileSystemRights]::Read; 
$if = [System.Security.AccessControl.InheritanceFlags]::ContainerInherit 
$if2 = [System.Security.AccessControl.InheritanceFlags]::ObjectInherit; 
$pf = [System.Security.AccessControl.PropagationFlags]::None; 
$act = [System.Security.AccessControl.AccessControlType]::Allow; 
$accessRule = New-Object System.Security.AccessControl.FileSystemAccessRule($everyone, $fsr, ($if,$if2), $pf, $act);

來源

2015-01-20 19:27:31 Trondh

的PowerShell將提供自動轉換字符串，所以你也可以這樣做：

$everyone = New-Object System.Security.Principal.SecurityIdentifier([System.Security.Principal.WellKnownSidType]::WorldSid, $null); 
$fsr = [System.Security.AccessControl.FileSystemRights]::Read; 
$if = [System.Security.AccessControl.InheritanceFlags]"ContainerInherit,ObjectInherit" 
$pf = [System.Security.AccessControl.PropagationFlags]::None; 
$act = [System.Security.AccessControl.AccessControlType]::Allow; 
$accessRule = New-Object System.Security.AccessControl.FileSystemAccessRule($everyone, $fsr, $if, $pf, $act);

事實上，如果你希望它是顯著的打字比較少（好快的命令行的東西時，你不關心清晰供日後閱讀），你可以做這樣的：

$everyone = New-Object System.Security.Principal.SecurityIdentifier([System.Security.Principal.WellKnownSidType]::WorldSid, $null); 
$accessRule = New-Object System.Security.AccessControl.FileSystemAccessRule $everyone, "Read", "ContainerInherit,ObjectInherit", "None", "Allow"

來源

2015-01-20 20:30:48

很有意思，我學到了新鮮玩意：） – 2015-01-20 20:45:01

如何在PowerShell中執行按位或（|）枚舉？

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