這個WHERE子句有什麼問題？

Question

是否有這個查詢不起作用的原因？如果我只是排除WHERE子句，下面的查詢將起作用。我需要知道它有什麼問題。我知道$ key的給定值存在於表中，那麼爲什麼這不起作用呢？

$q = "SELECT * WHERE t1.project=$key 
      FROM project_technologies AS t1 
      JOIN languages AS t2 
      ON t1.language = t2.key"; 

表的有以下字段：

project_technologies
- 關鍵
- 項目
- 語言

語言
- 關鍵
- 命名

Answer 1

WHERE在FROM/JOIN之後。

SELECT * 
FROM  project_technologies AS t1 
JOIN  languages AS t2 
ON  t1.language = t2.key 
WHERE  t1.project=$key 

Answer 2

FROM在SELECT聲明中出現在WHERE之前。

Answer 3

"SELECT * FROM project_technologies AS t1 INNER JOIN languages AS t2 ON t1.language = t2.key WHERE t.project = '$key'"; 

Answer 4

SELECT * 
      FROM project_technologies AS t1 
      JOIN languages AS t2 
      ON t1.language = t2.key 
      WHERE t1.project=$key 

Answer 5

您應該在FROM子句後，把你的WHERE子句。

Answer 6

SELECT * FROM project_technologies AS t1 
JOIN languages AS t2 
    ON t1.language = t2.key 
WHERE t1.project=$key 

的where應該是在年底（合併後）

Answer 7

在SQL你寫：

SELECT ... FROM表... WHERE條件

你把東西以錯誤的順序...

Answer 8

WHERE子句出現在FROM子句之後。

SELECT * 
FROM project_technologies as t1 
JOIN languages as t2 
on t1.language = ts.key 
WHERE t1.project = $key 

Answer 9

我認爲WHERE必須在FROM之後。你試過這個嗎？

$q = "SELECT * 
      FROM project_technologies AS t1 
      JOIN languages AS t2 
      ON t1.language = t2.key 
      WHERE t1.project=$key"; 

Answer 10

也許這應該是把它寫

"SELECT * FROM project_technologies AS t1 JOIN languages AS t2 ON t1.language = t2.key WHERE t1.project=$key";