2016-06-08 137 views
4

當我有2種方法異常反序列化JSON

public static string SerializeObject<T>(T value) 
{ 
    if (value == null) 
    { 
     return null; 
    } 

    var dictionaryObject = new Dictionary<string, object> { { typeof(T).Name, value } }; 

    var jsonString = JsonConvert.SerializeObject(dictionaryObject); 

    return jsonString; 
} 

public static T DeserializeObject<T>(string jsonString) 
{ 
    var objectValue = JsonConvert.DeserializeObject<Dictionary<string, object>>(jsonString); 
    return JsonConvert.DeserializeObject<T>(objectValue.Values.First().ToString()); 
} 

當我反序列化JSON字符串類型

ConcurrentDictionary<KeyValuePair<long, long>, IList<string>> 

我有一個例外:

Co uld不會將字符串'[1,1]'轉換爲字典鍵類型'System.Collections.Generic.KeyValuePair`2 [System.Int64,System.Int64]'。創建一個TypeConverter將字符串轉換爲鍵類型對象。 Path'[1,1]',第2行,第12位。

所以有人可以讓我看看它的正確工作方式嗎?

這裏是我的代碼:

var test = new ConcurrentDictionary<KeyValuePair<long, long>, IList<string>>(); 
test.TryAdd(new KeyValuePair<long, long>(1, 1), new List<string> { "Test" }); 

var se = SerializeObject(test); 

var de = DeserializeObject<ConcurrentDictionary<KeyValuePair<long, long>, IList<string>>>(se); 
+0

爲什麼你把它變成一個字典? – Toxicable

+0

你可能需要更多地解釋你想要完成的事情。不知道你想用Dictionary來解決什麼問題。 – d512

+0

@ user1334007:我想反序列化一個JSON字符串到類型爲ConcurrentDictionary的對象,IList > –

回答

3

我不知道這是否是最好的解決辦法,但是,請試試這個:

1)在this topic描述創建ContractResolver。

class DictionaryAsArrayResolver : DefaultContractResolver 
     { 
      protected override JsonContract CreateContract(Type objectType) 
      { 
       if (objectType.GetInterfaces().Any(i => i == typeof(IDictionary) || 
        (i.IsGenericType && 
        i.GetGenericTypeDefinition() == typeof(IDictionary<,>)))) 
       { 
        return base.CreateArrayContract(objectType); 
       } 

       return base.CreateContract(objectType); 
      } 
     } 

2)改了一下你的序列化/反序列化方法:

public static string SerializeObject<T>(T value, JsonSerializerSettings settings) 
     { 
      if (value == null) 
      { 
       return null; 
      } 

      var dictionaryObject = new Dictionary<string, object> { { typeof(T).Name, value } }; 
      var jsonString = JsonConvert.SerializeObject(dictionaryObject, settings); 

      return jsonString; 
     } 

     public static T DeserializeObject<T>(string jsonString, JsonSerializerSettings settings) 
     { 
      var objectValue = JsonConvert.DeserializeObject<Dictionary<string, object>>(jsonString, settings); 
      return JsonConvert.DeserializeObject<T>(objectValue.Values.First().ToString(), settings); 
     } 

3)檢查測試:

[TestMethod] 
     public void Test() 
     { 
      var test = new ConcurrentDictionary<KeyValuePair<long, long>, IList<string>>(); 
      test.TryAdd(new KeyValuePair<long, long>(1, 1), new List<string> { "Test" }); 

      JsonSerializerSettings settings = new JsonSerializerSettings(); 
      settings.ContractResolver = new DictionaryAsArrayResolver(); 

      var se = SerializeObject(test, settings); 

      var de = DeserializeObject<ConcurrentDictionary<KeyValuePair<long, long>, IList<string>>>(se, settings); 
     } 

我希望它有助於=)

+0

它的工作,感謝您的解決方案:) @Johnny Svarog –

+0

不用客氣=) –