2017-08-25 57 views
0

我有json對象,我試圖用jquery寫一個groupped_options。 我的JSON對象看起來像這樣分組選項用jquery選擇

data = {"01 CONSULT":[["1b Rules","40"]],"02 DEVELOPMENT":[],"03 QUALITY":[],"05 MARKETING":[["5e Research","66"]],"06 MISCELLANEOUS":[["6a Training","69"],["6b Meetings","70"]} 

我的下拉應該是這樣的:

**01 CONSULT** 
    1b Rules 
**02 DEVELOPMENT** 
**03 QUALITY** 
**05 MARKETING** 
    5e Research 
**06 MISCELLANEOUS** 
    6a Training 
    6b Meetings 

我的代碼目前看起來是這樣的。我無法在下拉列表中獲取父值,因爲我正在努力用grouped_options編寫jquery。

function change(data){ 
    $("#task_id").empty(); 
     for(var y in data){ 
     $("#task_id").append(
     $("<option></option>").attr("value", y).text(data[y]).appendTo("optgroup"); 
); 

}}

任何幫助將是appreciated..Thanks!

回答

1

您當前的代碼不附加任何OPTGROUP元素。也許你可以做這樣的事情:

data = {"01 CONSULT":[["1b Rules","40"]],"02 DEVELOPMENT":[],"03 QUALITY":[],"05 MARKETING":[["5e Research","66"]],"06 MISCELLANEOUS":[["6a Training","69"],["6b Meetings","70"]]} 
 

 
function change(data){ 
 
    var slct = $("#task_id") 
 
    slct.empty() 
 
    
 
    Object.keys(data).forEach(function(og) {     // for each data key 
 
    var optgroup = $("<optgroup></optgroup>", {label: og}) // create optgroup element 
 
    data[og].forEach(function(opt) {      // for each option 
 
     $("<option></option>", {        // create option element 
 
     value: opt[1], 
 
     text: opt[0] 
 
     }).appendTo(optgroup)        // append option to group 
 
    })   
 
    optgroup.appendTo(slct)        // append group to select 
 
    }) 
 
} 
 

 
change(data)
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script> 
 
<select id="task_id"></select>

1

我不知道這是否是在功能的完整代碼,但沒有創建一個OPTGROUP

var data = { 
 
    "01 CONSULT": [ 
 
    ["1b Rules", "40"] 
 
    ], 
 
    "02 DEVELOPMENT": [], 
 
    "03 QUALITY": [], 
 
    "05 MARKETING": [ 
 
    ["5e Research", "66"] 
 
    ], 
 
    "06 MISCELLANEOUS": [ 
 
    ["6a Training", "69"], 
 
    ["6b Meetings", "70"] 
 
    ] 
 
}; 
 

 

 

 

 
change(); 
 

 
function change() { 
 
    var $select = $('#task_id'); 
 
    for (d in data) { 
 
    var parent = d; 
 
    var children = data[d]; 
 
    console.log(d); 
 
    var $optgroup = $('<optgroup/>', { 
 
     label: d, 
 
    }).appendTo($select); 
 
    for (c in children) { 
 
     var child = data[d][c]; 
 
     $('<option/>', { 
 
     value: child, 
 
     html: child 
 
     }).appendTo($optgroup); 
 
    } 
 
    } 
 
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> 
 
<select id="task_id"> 
 
</select>