MySQL查詢只選擇日期

組的最後一排，我有以下查詢：MySQL查詢只選擇日期

SELECT ELO，日期（date_calculated）日期從users_historical_elo其中uid = 36 ORDER BY ID ASC

產生這樣的結果：

| elo | date

|984|2011-04-04

|1010|2011-04-04

|1036|2011-04-04

|1016|2011-04-08

|1000|2011-04-08

|944|2011-04-09

|973|2011-04-09

...

我需要幫助編寫一個查詢，按日期只選擇最後一個「elo」分組。所以輸出應該是：

| elo | date

|1036|2011-04-04

|1000|2011-04-08

|973|2011-04-09

...

謝謝！

來源

2011-05-29 newyuppie

你的意思'| 1016 | 2011-04-08'，對不對？ – 2011-05-29 01:00:09

哦，對不起，你有'按ID訂購'，好。 – 2011-05-29 01:01:44

http://stackoverflow.com/questions/3449757/sql-group-by-records-and-then-get-last-record-from-each-group – NAVEED 2011-05-29 01:09:23

如果id是表的主鍵，那麼這將做到：

SELECT elo 
    , date(date_calculated) AS date 
FROM users_historical_elo 
    JOIN 
    (SELECT MAX(id) AS id 
     FROM users_historical_elo 
     WHERE uid =36 
     GROUP BY date(date_calculated) 
    ) AS grp 
    ON grp.id = users_historical_elo.id 
ORDER BY grp.id ASC

來源

2011-05-29 01:05:48

它完美的工作，謝謝 – newyuppie 2011-05-29 02:43:54

道德的額外信貸;）如果我有相同的情況，我怎麼能修改這個查詢，但我需要選擇按日期分組的*倒數第二個* elo？ – newyuppie 2011-05-29 21:01:05

嘗試：

SELECT elo, date(date_calculated) date FROM users_historical_elo WHERE uid =36 group by date order by id asc

來源

2011-05-29 01:02:49 kevinAlbs

我認爲你需要使用MAX和GROUP BY。見http://www.tutorialspoint.com/mysql/mysql-max-function.htm

我認爲這會工作

SELECT elo, MAX(date(date_calculated)) date 
FROM users_historical_elo 
WHERE uid =36 
GROUP BY elo 
ORDER BY id asc

來源

2011-05-29 01:03:27 cordsen

此：

SELECT elo, MAX(date) FROM users_historical_elo

將返回ELO和任何ELO，這似乎是你所要求的最後日期？

來源

2011-05-29 01:04:22 Rob

MySQL查詢只選擇日期

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