使用谷歌腳本解析XML數據

Question

我一直在嘗試將XML feed轉換爲人類可讀形式，但沒有成功。我曾嘗試看到在tutorails部分給出的例子，但它太複雜。請有人可以幫我解決問題。我可以做得很好，直到解析XML。

我使用谷歌腳本，輸出必須在谷歌文檔。

這裏是我想出了到現在爲止

var response = UrlFetchApp.fetch("http://getRecords.php?oauth_token=3e73c7&lat="+lat+"&lon="+lon+"&searchFor="+text+"&miles=100&response_type=xml"); 

    var doc = Xml.parse(response.getContentText(), true) 
var root = doc.getElement(); 
var entryList = "<ul>\n"; 

var entries = root.getElements("details"); 

    for (var i=0; i<entries.length; i++) { 
    var e = entries[i]; 
    var name = e.getElement("name").getText(); 

    } 



    entryList += "<li>name </li>" + name; 


    entryList += "</ul>\n"; 
    return entryList; 

這裏是XML

<record> 
<details> 
<id>212929</id> 
<distance>0</distance> 
<category cat="8" sub="202" id="1201">General</category> 
<name>Text Book Center</name> 
<short_desc>One of Kenya's finest</short_desc> 
<long_desc> 
One of Kenya's leading bookshops, the Text Book Center offers a wide selection of titles. There is everything here from textbooks to fiction to the latest Information Technology titles. The range of maps is especially impressive. The shop is spacious and cool, giving shoppers plenty of room to browse the shelves upon shelves of books. Look out for the regular special offers. 
</long_desc> 
<address> 
<address1>Kijabe Street</address1> 
<city>Nairobi</city> 
<country>Kenya</country> 
<latitude>0</latitude> 
<longitude>0</longitude> 
</address> 
<neighborhood>Downtown</neighborhood> 
<phone>+254 2 330 340</phone> 
<email>info@tbc.co.ke</email> 
<open_hours>8am-1pm; 2pm-5.30pm Mon-Sat.</open_hours> 
</details> 
</record> 
</records> 

我如何刪除標籤和剛打印出來的文檔。請幫助

謝謝

Answer 1

看起來根節點開放標記丟失。它是原始文檔嗎？或者只是粘貼錯誤？

嘗試這樣

var response = UrlFetchApp.fetch("http://getRecords.php? oauth_token=3e73c7&lat="+lat+"&lon="+lon+"&searchFor="+text+"&miles=100&response_type=xml"); 
var doc = Xml.parse(response.getContentText(), true); 
var records = doc.records.getElements("record"); 
var entryList = "<ul>\n"; 

for (var i=0; i < records.length; i++) { 
    var details = records[i].details; 
    var name = details.name.getText(); 
    entryList += "<li>" + name + "</li>\n"; 
} 

entryList += "</ul>\n"; 
return entryList;