問題與多個單詞

Question

說我有問題計數詞彙出現的是，我不完全知道如何重置我的字數。我創建了一個單詞搜索，但是當我計算出10個不同單詞出現的次數時，它與第一個單詞保持相同的數字。我相信我遇到的問題是我用一個for循環

輸出

boy appeared 3 times 
Snape appeared 3 times 
Dumbledore appeared 3 times 
he appeared 3 times 
her appeared 3 times 
the appeared 3 times 
it appeared 3 times 
is appeared 3 times 
will appeared 3 times 
all appeared 3 times 

它應該是什麼樣子

boy appeared 3 times 
Snape appeared 7 times 
Dumbledore appeared 4 times 
he appeared 27 times 
her appeared 4 times 
the appeared 13 times 
it appeared 6 times 
is appeared 12 times 
will appeared 2 times 
all appeared 3 times 

通過閱讀我的代碼我敢肯定，我已經比現在更復雜。我將不勝感激我提出的任何建議和更正。

的完整代碼提前

#include <iostream> 
#include <fstream> 
#include <string> 
#include <sstream> 
#include <vector> 

// Main Function 
int main() 
{ 
    // Declaration 
    std::string list, passage, word[10]; 
    std::ifstream listFile("WordList.txt", std::ios::in); 
    std::ifstream passageFile("HarryPotterPassage.txt", std::ios::in); 
    std::vector<std::string> vec_wordList, vec_passage; 


    /* Read a file that contains a list of 10 words */ 
    if (listFile.is_open()) 
    { 
     // Store text file in a vector 
     while (listFile) 
     { 
      listFile >> list; 
      vec_wordList.push_back(list); 
     } 

     // Assign vector to individual strings 
     for (int i = 0; i < 10; i++) 
     { 
      word[i] = vec_wordList[i]; 
     } 

     // Close file 
     listFile.close(); 
    } 
    else 
     std::cout << "No file found.\n"; 


    /* Read another file containing a paragraph */ 
    if (passageFile.is_open()) 
    { 
     while (passageFile) 
     { 
      // Store text file in a string 
      std::getline(passageFile, passage); 
     } 

     // Close file 
     passageFile.close(); 
    } 
    else 
     std::cout << "No file found.\n"; 

    //std::cout << passage << '\n'; 


    /* Count the number of words from the first file 
     from the second file that contains the paragraph */ 
    size_t count = 0; 
    std::string::size_type pos = 0; 

    for (int i = 0; i < 10; i++) 
    { 
     while ((pos = passage.find(word[i], pos)) != std::string::npos) 
     { 
      count++; 
      pos += word[i].size(); 
     } 

     std::cout << word[i] << " appeared " << count << " many times\n"; 
    } 

    system("pause"); 
    return 0; 
} 

感謝。

Answer 1

您需要在外部循環的每次迭代的開始重置count和pos。

換句話說，改變這種：

size_t count = 0; 
std::string::size_type pos = 0; 
for (int i = 0; i < 10; i++) 
{ 
    ... 
} 

要這樣：

for (int i = 0; i < 10; i++) 
{ 
    size_t count = 0; 
    std::string::size_type pos = 0; 
    ... 
} 

順便說一句，我也想改變這種狀況10到sizeof(word)/sizeof(*word)。

Answer 2

您使用Word來代替字[9] [I]，所以你得到的最後一個字，而不是每個人的結果。 嘗試：

for (int i = 0; i < 10; i++) 
{ 
    while ((pos = passage.find(word[i], pos)) != std::string::npos) 
    { 
     count++; 
     pos += word[i].size(); 
    } 

    std::cout << word[i] << " appeared " << count << " many times\n"; 
}