2015-02-08 40 views
1

我使用的是iOS上的libxslt,和我是從什麼應該是簡單的XSLT,如獲取編譯錯誤:的libxslt:編譯錯誤

compilation error: file /Users/yada/Library/Developer/CoreSimulator/Devices/ACE15E20-3230-4966-ACDE-DCADABF48B32/data/Containers/Bundle/Application/A4EC9B34-3A96-42E0-B58F-6EB44C942874/appname.app/upconversion-options.xsl line 19 element function 
xsltStylePreCompute: unknown xsl:function 
compilation error: file /Users/yada/Library/Developer/CoreSimulator/Devices/ACE15E20-3230-4966-ACDE-DCADABF48B32/data/Containers/Bundle/Application/A4EC9B34-3A96-42E0-B58F-6EB44C942874/appname.app/upconversion-options.xsl line 20 element param 
element param only allowed within a template, variable or param 

...還有更多類似的是,當我做到這一點:

xmlSubstituteEntitiesDefault(1); 
xmlLoadExtDtdDefaultValue = 1; 

NSString * pMathMLTocMathMLXSLPath = [[NSBundle mainBundle] pathForResource:@"upconversion-options" ofType:@"xsl"]; 
xsltStylesheetPtr pMathMLTocMathMLXSLStyleSheet = xsltParseStylesheetFile((const xmlChar *)[pMathMLTocMathMLXSLPath cStringUsingEncoding:NSUTF8StringEncoding]); 

XSL文件看起來是這樣的:

<xsl:stylesheet version="2.0" 
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
    xmlns:xs="http://www.w3.org/2001/XMLSchema" 
    xmlns:s="http://www.ph.ed.ac.uk/snuggletex" 
    xmlns="http://www.w3.org/1998/Math/MathML" 
    exclude-result-prefixes="xs s" 
    xpath-default-namespace="http://www.w3.org/1998/Math/MathML"> 

    <xsl:function name="s:get-boolean-option" as="xs:boolean"> 
    <xsl:param name="upconversion-options" as="element(s:upconversion-options)"/> 
    <xsl:param name="name" as="xs:string"/> 
    <xsl:sequence select="boolean($upconversion-options/s:option[@name=$name]/@value='true')"/> 
    </xsl:function> 

    <xsl:function name="s:get-upconversion-option" as="xs:string?"> 
    <xsl:param name="upconversion-options" as="element(s:upconversion-options)"/> 
    <xsl:param name="name" as="xs:string"/> 
    <xsl:sequence select="$upconversion-options/s:option[@name=$name]/@value"/> 
    </xsl:function> 

    <xsl:function name="s:get-symbol-assumption" as="element(s:symbol)?"> 
    <xsl:param name="element" as="element()"/> 
    <xsl:param name="upconversion-options" as="element(s:upconversion-options)"/> 
    <xsl:sequence select="$upconversion-options/s:symbol[deep-equal(*, $element)]"/> 
    </xsl:function> 

    <xsl:function name="s:is-assumed-symbol" as="xs:boolean"> 
    <xsl:param name="element" as="element()"/> 
    <xsl:param name="upconversion-options" as="element(s:upconversion-options)"/> 
    <xsl:param name="assume" as="xs:string"/> 
    <xsl:sequence select="exists($upconversion-options/s:symbol[@assume=$assume and deep-equal($element, *)])"/> 
    </xsl:function> 

    <xsl:function name="s:is-assumed-function" as="xs:boolean"> 
    <xsl:param name="element" as="element()"/> 
    <xsl:param name="upconversion-options" as="element(s:upconversion-options)"/> 
    <xsl:sequence select="s:is-assumed-symbol($element, $upconversion-options, 'function')"/> 
    </xsl:function> 

</xsl:stylesheet> 

有什麼建議?

回答

2

libxslt不支持XSLT 2.0。您需要使用尚未離開測試版的Saxon/C,或者還原爲XSLT 1.0。如果您恢復到1.0並需要額外的功能,請查看EXSLT。