以下是我創建的PHP文件的代碼。將數據從`HTML`登錄表單傳遞給`PHP`,以便從'MySQL'數據庫中恢復數據
<?php
$db = mysqli_connect("127.0.0.1","root","toor","mylib")
or die('Error connecting to MySQL server.');
?>
<html>
<head>
</head>
<h1>PHP connect to MySQL</h1>
</body>
</html>
<?php
$query = "SELECT * FROM book WHERE bookid IN (SELECT bookid FROM studentbook WHERE studid =
$_POST['stuid'])";
mysqli_query($db, $query) or die('Error querying database.');
$result = mysqli_query($db, $query);
$row = mysqli_fetch_row($result);
foreach($row as $a)
print($a." ");
?>
現在,我期待從HTML登錄頁面獲取studid
並將其傳遞 使用POST
方法來檢索對應的值(studid)數據的PHP文件中輸入,從MySQL
數據庫 - 我的意思是使用mysqli_query()
功能。
但是當我嘗試運行我上面顯示的代碼,我想出了下面Error
:
Parse error: syntax error, unexpected '' (T_ENCAPSED_AND_WHITESPACE), expecting identifier (T_STRING) or variable (T_VARIABLE) or number (T_NUM_STRING) in /opt/lampp/htdocs/connectivity.php on line 13
請指引我在以下方面:
1)如何從Login page
獲得值並使用post
方法將它傳遞給PHP file
?
2)如何糾正上述錯誤?
[如何在mysqli-query中使用$ \ _ POST變量? (PHP)](http://stackoverflow.com/questions/30360721/how-to-use-a-post-variable-in-an-mysqli-query-php) – mickmackusa