子查詢PHP的MySQL

Question

我有這樣的子查詢：

$sql = "SELECT * FROM curriculum WHERE ci in (SELECT curriculum FROM contactados WHERE activado = 'si' AND empresa = '".$_SESSION['emp']."')"; 
    echo "Rows: ".@mysql_num_rows($sql); 
    $result = mysql_query($sql, $link) or die(mysql_error($link)); 
     while($fila = mysql_fetch_array($result)){ 

     echo $fila['nombres']." ".$fila['apellidos']or die("error"); 


     }  

但doesn't的工作，我不知道爲什麼

Answer 1

我希望這對你的工作......

$sql = "SELECT `a`.*, `b`.`curriculum` FROM `curriculum` AS `a` 
     LEFT JOIN `contactados` AS `b` ON `a`.`ci` = `b`.`curriculum` 
     WHERE `b`.`activado` = 'si' AND `b`.`empresa` = '".$_SESSION['emp']."'";