PHP JSON值檢索錯誤

Question

我必須從我的PHP編碼JSON文件中檢索JSON值問題

這是我PHP代碼：

$i = 0; 
$qinfo = ''; 
$j=0; 
$qry = "SELECT qid, q_title, q_question FROM questions WHERE qid = 1"; 
$result = mysql_query($qry); 
$data = array(); 

while ($r = mysql_fetch_array($result)) { 

    $qinfo[$i]['qid'] = $r['qid']; 
    $qinfo[$i]['q_title'] = $r['q_title']; 
    $qinfo[$i]['q_question'] = $r['q_question']; 

    $qry2 = "SELECT aid, answer FROM answers WHERE qid=".$r['qid']." "; 
    $result2 = mysql_query($qry2); 

    while ($r2 = mysql_fetch_array($result2)) { 

     $qinfo[$j]["Ans"]["aid"] = $r2['aid']; 
     $qinfo[$j]["Ans"]["aid"] = $r2['answer']; 

     $j++; 
    }PHP 
    $i++; 
} 
echo json_encode($qinfo); 

這是輸出JSON：

[{ 
    "qid": "1", 
    "q_title": "This is first question title", 
    "q_question": "This is first question description", 
    "Ans": { 
     "aid": "26", 
     "answer": "This is first answer" 
    } 
}, { 
    "Ans": { 
     "aid": "27", 
     "answer": "This is second answer" 
    } 
}, { 
    "Ans": { 
     "aid": "28", 
     "answer": "This is third" 
    } 
}] 

1. 這個JSON格式正確嗎？簡單地解釋：我得到1個問題的答案。

這裏是我試圖獲得結果的jQuery代碼。

$(document).ready(function() { 
    $.ajax({ 
     type: "POST", 
     cache: false, 
     dataType:"json", 
     url: 'data.php', 
     success: function(data){ 
      $('.show_divis').each(function (index, value){ 
       var data_votes = ''; 

       data_votes += '<div style="color:#000">'+data[index].q_title+'</div>'; 
       data_votes += '<div style="color:#555">'+data[index].q_question+'</div>'; 

       $(this).html(data_votes).fadeOut(300).fadeIn(400); 

       $('.show_divis2').each(function (index, value){ 
        var data_votes2 = ''; 

        data_votes2 += '<div style="color:#000">'+data[index].Ans.aid+'</div>'; 
        data_votes2 += '<div style="color:#555">'+data[index].Ans.answer+'</div>'; 

        $(this).html(data_votes2).fadeOut(300).fadeIn(400); 
       }); 
      }); 
     } 
    }); 
}); 

它會正確顯示的問題標題和描述。但只顯示1個答案？根據我的JSON文件有3個答案。我想在問題下顯示3個答案。我可以改變我的JSON格式嗎？ 在此先感謝！

Answer 1

您的JSON是有效的，但格式不正確，因爲它應該有這樣一個節點下所有的答案：

[{ 
    "qid": "1", 
    "q_title": "This is first question title", 
    "q_question": "This is first question description", 
    "Ans": [{ 
     "aid": "26", 
     "answer": "This is first answer" 
    }, 
    { 
     "aid": "27", 
     "answer": "This is second answer" 
    }, 
    { 
     "aid": "28", 
     "answer": "This is third" 
    }] 
}] 

要獲得上述JSON格式，請改變你的PHP代碼如下：

$i = 0; 
$qinfo = array(); 
$qry = "SELECT qid, q_title, q_question FROM questions WHERE qid = 1"; 
$result = mysql_query($qry); 

while ($r = mysql_fetch_array($result)) { 

    $qinfo[$i]['qid'] = $r['qid']; 
    $qinfo[$i]['q_title'] = $r['q_title']; 
    $qinfo[$i]['q_question'] = $r['q_question']; 

    $qry2 = "SELECT aid, answer FROM answers WHERE qid=".$r['qid']." "; 
    $result2 = mysql_query($qry2); 

    $j = 0; 
    while ($r2 = mysql_fetch_array($result2)) { 

     $qinfo[$i]["Ans"][$j]["aid"] = $r2['aid']; 
     $qinfo[$i]["Ans"][$j]["answer"] = $r2['answer']; 

     $j++; 
    } 
    $i++; 
} 
echo json_encode($qinfo); 

而jQuery的部分：

$(document).ready(function() { 
    $.ajax({ 
     type: "POST", 
     cache: false, 
     dataType:"json", 
     url: 'data.php', 
     success: function(data){ 
      var data_votes = ''; 

      $.each(data, function (index, questions){ 
       //console.log(questions); 
       data_votes += '<div style="display: block; background-color: #eee; margin: 5px 0px; padding: 5px;">'; 
       data_votes += '<h2 style="padding: 5px; margin: 0px;">'+questions.q_title+'</h2>'; 
       data_votes += '<p style="padding: 5px;">'+questions.q_question+'</p>'; 

       $.each(questions.Ans, function (index, answers){ 
        //console.log(answers); 
        data_votes += '<div style="color:#555; padding: 5px; margin: 2px 0px; background-color: #ccc;" id="answer_'+answers.aid+'">'+answers.answer+'</div>'; 
       }); 
       data_votes += '</div>'; 
      }); 
      // Add your reference to your desired html element instead of "BODY" 
      $('body').append(data_votes); 
     } 
    }); 
});