ios如何提取for循環中的數組的所有rangeOfString？

Question

我想提取NSarray的所有「女兒」。

例如，NSArray中作出這樣的：

hello 
hi 
hello daughter 
my goodness 
daughter (someone) 
my daughter 
how are you? 
etc. 

而且我想提取包含「女兒」的所有行。你能指出我正確的方向嗎？

我當前的代碼是：

for (NSString *mystring in self.array) 
{ 
    if ([mystring rangeOfString:searchText].location!=NSNotFound) 

{ 
    NSUInteger idx = [self.array indexOfObject:mystring]; 
    [self.filterarray addObject: mystring]; 
} 
} 

Answer 1

NSArray *lines = ...; 
NSArray *filteredLines = [lines filteredArrayUsingPredicate:[NSPredicate predicateWithBlock:^BOOL(NSString *string, NSDictionary *bindings) { 
    return ([string rangeOfString:searchText].location != NSNotFound); 
}]]; 

（需要iOS 4.0或更高版本）

如果需要支持較早的系統版本使用：

NSArray *lines = ...; 
NSArray *filteredLines = [lines filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"(SELF contains[c] %@)", searchText]]; 

（需要iOS 3.0或更高版本）

Answer 2

NSString *textViewText = @「hello hi hello daughter my goodness daughter (someone) my daughter how are you? etc.」; 

NSMutableAttributedString *attributedString = [[NSMutableAttributedString alloc] initWithString:textViewText]; 


NSArray *highlightWords = @[@「daughter」,@」hello」]; 

for(NSString *word in highlightWords) 
{ 
    NSRange range = NSMakeRange(0, textViewText.length); 
    do{ 
     range = [textViewText rangeOfString:word options:NSCaseInsensitiveSearch range:range]; 
     [attributedString addAttribute:NSForegroundColorAttributeName value:[UIColor redColor] range:range]; 
     if (range.location != NSNotFound) 
      range = NSMakeRange(range.location + 1, textViewText.length - (range.location + 1)); 
    }while(range.location != NSNotFound); 

}