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我有以下多維數組生成動態菜單搜索多維數組:使用鍵和值的對
[
"3gnitjUdm6" => [
"name" => "Overview",
"slug" => "overview",
"priority" => 1,
"pages" => [
"i3OQlLqgqO" => [
"name" => "Dashboard",
"url" => "",
"priority" => 2,
"subpages" => [],
],
"izma1tvjGd" => [
"name" => "Settings",
"url" => "/settings",
"priority" => 4,
"subpages" => [],
]
]
],
"IcSujiIx9A" => [
"name" => "Content",
"slug" => "content",
"priority" => 5,
"pages" => [
"3KJdhtCRuI" => [
"name" => "Users",
"url" => "/users",
"priority" => 2,
"subpages" => [],
],
"M3zw9hq6rW" => [
"name" => "Pets",
"url" => "/pets",
"priority" => 4,
"subpages" => [],
],
],
],
]
每個部分包含的頁的陣列,並且每個頁面可以包含子頁面的陣列。我需要能夠搜索這個數組來找到使用鍵和值對的部分的鍵。
private function _find_section($key, $value) {
foreach($this->menu as $section_key => $section) {
if(is_array($section[$key])) {
foreach($section[$key] as $sub_key => $sub) {
if($sub_key === $value) {
return $section_key;
}
}
} elseif(is_string($section[$key])) {
if($section[$key] === $value) {
return $section_key;
}
} else {
return false;
}
}
}
運行下面的代碼:
_find_section('name', 'Content')
始終返回false。
您的功能對我來說確實很好。你可以打印'$ this-> menu'並確保它與問題中發佈的數組相同 –