如何從緩衝讀取器輸入字符串？

Question

林使用過多使用掃描儀主要是和想太多嘗試使用一個緩衝的讀者： 繼承人是我迄今爲止

import java.util.*; 
import java.io.*; 
public class IceCreamCone 
{ 
// variables 
String flavour; 
int numScoops; 
Scanner flavourIceCream = new Scanner(System.in); 

// constructor 
public IceCreamCone() 
{ 

} 
// methods 
public String getFlavour() throws IOexception 
{ 
    try{ 

    BufferedReader keyboardInput; 
    keyboardInput = new BufferedReader(new InputStreamReader(System.in)); 
    System.out.println(" please enter your flavour ice cream"); 
    flavour = keyboardInput.readLine(); 
    return keyboardInput.readLine(); 
    } 
    catch (IOexception e) 
    { 
     e.printStackTrace(); 
    } 
} 

IM相當肯定獲得一個int，你可以說

Integer.parseInt(keyboardInput.readLine()); 

但什麼這樣做，你應該簡單地做我做，如果我想要一個字符串

Answer 1

keyboardInput.readLine()已經返回一個字符串：

return keyboardInput.readLine(); 

（更新）

的readLine方法拋出IOException。你要麼拋出異常：

public String getFlavour() throws IOException { 
    ... 
} 

或者你在你的方法中處理它。

public static String getFlavour() { 
    BufferedReader keyboardInput = null; 
    try { 
     keyboardInput = new BufferedReader(new InputStreamReader(System.in)); 
     System.out.println(" please enter your flavour ice cream"); 
     // in this case, you don't need to declare this extra variable 
     // String flavour = keyboardInput.readLine(); 
     // return flavour; 
     return keyboardInput.readLine(); 
    } catch (IOException e) { 
     // handle this 
     e.printStackTrace(); 
    } 
    return null; 
}