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我在swift ios中創建了一個HTTP POST請求。當我在php文件中獲取一個post變量時,它顯示爲空白,我沒有得到一個變量值。在我的swift代碼下面,看看它。獲取swift post變量時出錯
var dataString = "name=john&type=student"
var request : NSMutableURLRequest = NSMutableURLRequest()
request.URL = NSURL(string: "http://www.example.com/example.php")
var postString = (dataString as NSString).dataUsingEncoding(NSUTF8StringEncoding)
request.HTTPMethod = "POST"
request.setValue("application/json", forHTTPHeaderField: "Content-Type")
request.HTTPBody = postString
var connection = NSURLConnection(request: request, delegate: self, startImmediately: false)
func connection(didReceiveResponse: NSURLConnection!, didReceiveResponse response: NSURLResponse!) {
//New request so we need to clear the data object
println(response)
}
PHP代碼:
<?php
echo $_POST['name'];
?>
任何人都可以建議我應該得到一個變量的值做。由於
的
Content-Type
實際上,它__does__回答這個問題。問題在於他以x-www-form-urlencoded格式將數據作爲主體發送,並將其稱爲JSON。由於他告訴PHP它是JSON,因此它不會被解碼爲POST參數到_POST。 – 2014-10-10 19:31:14現在它正在工作。謝謝@David – Viju 2014-10-11 05:35:46