從SQL查詢中排除記錄

給定一個或多個owner_ids（例如2,4和6），我想返回鏈接到owners的resources.id的列表owners_has_resources。沒問題，我可以做SELECT DISTINCT ohr.resources_id FROM owners_has_resources ohr WHERE ohr.owners_id IN (2,4,6);從SQL查詢中排除記錄

現在我堅持的部分。我想回的resources.id列表與上面相同，但排除任何也與未缺失的業主（由owners.deleted!=true確定），其中的鏈接不會被刪除（由owners_has_resources.deleted!=true確定）

它可以假設owners.deleted是true所有最初提供owners_ids（即2，4，6）

例如，給定owners_ids 2和4，我應該返回resources_id 2和3。注意，我的意思是說deleted=TRUE表明它被刪除了，但是因爲已經發布了使用前面的答案，所以我不會編輯這個問題。相反，下面的真值表顯示了owner_not_deleted和resource_not_deleted。

+-----------+-------------------+--------------+----------------------+ 
| owners_id | owner_not_deleted | resources_id | resource_not_deleted | 
+-----------+-------------------+--------------+----------------------+ 
|   2 | FALSE    |   1 | TRUE     | 
|   2 | FALSE    |   2 | TRUE     | 
|   4 | FALSE    |   2 | TRUE     | 
|   4 | FALSE    |   3 | TRUE     | 
|   5 | TRUE    |   1 | FALSE    | 
|   5 | TRUE    |   2 | TRUE     | 
|   7 | TRUE    |   2 | FALSE    | 
+-----------+-------------------+--------------+----------------------+ 

owners 
- id (INT PK) 
- name, etc 
- deleted (true/false) 

resources 
- id (INT PK) 
- name, etc 

owners_has_resources 
- owners_id (INT PK REFERENCES owners.id) 
- resources_id (INT PK REFERENCES resources.id) 
- deleted (true/false)

來源

2016-03-02 user1032531

你的用戶表是什麼？這張桌子是和其他人聯繫在一起的嗎？ – Wistar

對不起，錯字。這應該是'所有者'。我會更新。 – user1032531

這似乎很明顯，你需要什麼。但我會給予懷疑的好處。你可以顯示一個小數據樣本。這樣我可以確定你在問什麼？ –

什麼

SELECT DISTINCT ohr.resources_id 
FROM owners_has_resources ohr 
JOIN owners o ON ohr.owners_id = o.id 
WHERE ohr.owners_id IN (2,4,6) 
AND (o.deleted = FALSE OR ohr.deleted = FALSE);

來源

2016-03-02 15:55:30 Wistar

我認爲它需要'o.deleted = FALSE 或ohr.deleted = FALSE'，但這似乎會導致其他問題。 – user1032531

@ user1032531我做了更改。該查詢面臨什麼問題？ – Wistar

鑑於您的第一個查詢和我的編輯帖子中的虛構數據，它將僅返回resources_id＃3，並且您編輯的查詢將返回＃1，＃2和＃3。它應該只返回＃2和＃3。 – user1032531

首先，你選擇你想要，那麼你只能選擇那些不被非刪除的業主引用在NOT EXISTS塊

SELECT DISTINCT ohr.resources_id 
FROM owners_has_resources ohr 
JOIN owners o ON ohr.owners_id = o.id 
WHERE ohr.owners_id IN (2,4,6) 
AND NOT EXISTS (
    SELECT NULL FROM owners_has_resources ohr2 
    JOIN owners o2 ON ohr2.owners_id = o2.id 
    WHERE ohr2.deleted=FALSE 
    AND o2.deleted=FALSE 
    AND ohr.resources_id=ohr2.resources_id 
)

來源

2016-03-02 16:01:26 StephaneM

謝謝StephaneM。需要稍微調整一下。 – user1032531

SELECT DISTINCT ohr1.resources_id 
FROM owners_has_resources ohr1 
LEFT OUTER JOIN owners_has_resources ohr2 ON ohr2.resources_id=ohr1.resources_id AND ohr2.deleted = TRUE 
LEFT OUTER JOIN owners o ON o.id=ohr2.owners_id AND ohr2.deleted = TRUE 
WHERE ohr1.owners_id IN (2,4,6) AND o.id IS NULL;

數據或

SELECT DISTINCT ohr1.resources_id 
FROM owners_has_resources ohr1 
LEFT OUTER JOIN owners_has_resources ohr2 ON ohr2.resources_id=ohr1.resources_id 
LEFT OUTER JOIN owners o ON o.id=ohr2.owners_id 
WHERE ohr1.owners_id IN (2,4,6) AND o.id IS NULL AND ohr2.deleted = TRUE AND ohr2.deleted = TRUE;

我希望對一種方法是否比其他方法更好的評論。

來源

2016-03-03 12:53:47 user1032531

從SQL查詢中排除記錄

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