聚合相同的記錄

Question

出現了Oracle數據庫的情況下，我想創建兩個表具有相同的列的報告 表A包括id, code, name和表B包括id, code, name太 現在我想創建一個報告，計數和組數據都表給出結果如下：

Id1, code1, name1, count (the occurrence of this combination in both tables)

Id2, code2, name2, count (the occurrence of this combination in both tables)

我怎麼能achiev e使用查詢得到上述結果？重要的事實是有時某個表中可能找不到特定的項目，因此總計數將是在另一個表中找到的計數。可能的結果將是

idn, coden, namen, count of occurrence which found in one of the tables

Answer 1

這樣寫：

SELECT id, code, name, count(*) 
FROM (
    SELECT id, code, name FROM table1 
    UNION ALL 
    SELECT id, code, name FROM table2 
) t 
GROUP BY id, code, name 

如果你想保留的信息如何每個表格中出現多次(id, code, name)組合，可以使用au色譜柱：

SELECT 
    id, 
    code, 
    name, 
    count(*) AS "Occurrence in both tables", 
    count(CASE WHEN t = 'table1' THEN 1 END) AS "Occurrence in table1", 
    count(CASE WHEN t = 'table2' THEN 1 END) AS "Occurrence in table2" 
FROM (
    SELECT id, code, name, 'table1' AS t FROM table1 
    UNION ALL 
    SELECT id, code, name, 'table2' AS t FROM table2 
) t 
GROUP BY id, code, name 

Answer 2

select id,name,count from 
(
select id as id , name as name, count as count from table1 
union 
select id as id , name as name, count as count from table2 
) 

，如果你的意思是重要的結果，然後

select count(*) from 
(
    select id,name,count from 
    (
    select id as id , name as name, count as count from table1 
    union 
    select id as id , name as name, count as count from table2 
    ) 
)