0
select users.*, user_address.*, user_kyc_details.* , user_nominee.*, user_bank_details.*
from users, user_address, user_kyc_details, user_nominee, user_bank_details
where user_address.user_id=users.id and user_kyc_details.user_id=users.id and user_nominee.user_id=users.id and user_bank_details.user_id=users.id
如何直接在$ query-> createCommand()中運行此操作。作爲參數我試過但它不工作Yii加入查詢結果不像預期的那樣
上述查詢工作正常,並給出了預期的結果,但當我使用連接使用Yii像下面給出它給了我奇怪的結果(即不加入適當的ID和user_id )
$ query = new Query;
$query->select([
'users.*',
'user_address.*'
'user_kyc_details.*',
'user_nominee.*',
'user_bank_details.*'
])
->from('users')
->join('INNER JOIN', 'user_address','user_address.user_id = users.id')
->join('INNER JOIN', 'user_kyc_details','users.id =user_kyc_details.user_id')
->join('INNER JOIN', 'user_nominee','users.id =user_nominee.user_id')
->join('INNER JOIN', 'user_bank_details','users.id =user_bank_details.user_id');
$command = $query->createCommand();
$data = $command->queryAll();
任何幫助,將不勝感激
選擇用戶做查詢。*,user_address。*,user_kyc_details。*,user_nominee。*, user_bank_details。*來自用戶,user_address,user_kyc_details,user_nominee,user_bank_details,其中user_address.user_id = users.id和user_kyc_details.user_id = users.id和user_nominee.user_id = users.id 和user_bank_details.user_id = users.id –