2013-02-19 36 views
1

如何通過SNMP獲得此結果?如何通過SNMP將Portchannel映射到接口

顯示以太總結

Group Port-channel Protocol Ports 
------+-------------+-----------+----------------------------------------------- 
1  Po1(RU)   -  Gi2/3(P)  Gi3/3(P)  
2  Po2(RU)   -  Gi2/4(P)  Gi3/4(P)  
3  Po3(SU)   -  Gi2/2(P)  Gi3/2(P)  
9  Po9(SU)   -  Gi2/12(P)  Gi3/12(P)  
421 Po421(SU)  -  Gi11/1(P)  Gi11/2(P)  Gi11/3(P)  
          Gi11/4(P)  
422 Po422(SU)  -  Gi11/5(P)  Gi11/6(P)  Gi11/7(P)  
          Gi11/8(P)  
423 Po423(SU)  -  Te12/1(P)  

回答

0

這是有點晚了,但研究類似的事情我遇到this Cisco forums post來了。據報道在IEEE8023-LAG-MIB以下對象:

IEEE8023-LAG-MIB::dot3adAggPortSelectedAggID.28 = INTEGER: 337 
IEEE8023-LAG-MIB::dot3adAggPortSelectedAggID.82 = INTEGER: 337 

IEEE8023-LAG-MIB::dot3adAggPortAttachedAggID.28 = INTEGER: 337 
IEEE8023-LAG-MIB::dot3adAggPortAttachedAggID.82 = INTEGER: 337 

ifName.28 = Gi2/4 
ifName.82 = Gi3/10 
ifName.337 = Po1 

在同樣的環境中show etherchannel summary命令將導致:

+------+-------------+-----------+---------------------------------+ 
| Group|Port-channel |Protocol | Ports       | 
+------+-------------+-----------+---------------------------------+ 
| 1 | Po1(SU)  | LACP  | Gi2/4(P)  Gi3/10(P)  | 
+------+-------------+-----------+---------------------------------+