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我有一個簡單的方法,它不工作,因爲它應該 - 想使用準備好的語句,但不知何故它不執行;相反,原始查詢工作得很好。PDO不執行語句
可能是什麼問題?我應該將一些額外的參數傳遞給pdo方法嗎?
$_POST['sequence'] = [
0 => 2,
1 => 1
];
if (!empty($_POST['sequence'])) {
$query = '
UPDATE '.$this->db->backtick($this->controller->table).'
SET `sequence` = CASE `id`'
;
foreach ($_POST['sequence'] as $sequence => $id) {
$values[':id'.$id] = $id;
$values[':sequence'.$sequence] = $sequence;
$query .= ' WHEN :id'.$id.' THEN :sequence'.$sequence;
}
$values[':ids'] = implode(',', array_values($_POST['sequence']));
$query .= ' END WHERE `id` IN (:ids)';
$statement = $this->db->handle->prepare($query);
$statement->execute($values); //doesn't work
//$query2 = str_replace(array_keys($values), array_values($values), $query);
//$this->db->handle->query($query2); works
}
你收到一條錯誤消息帕拉姆不綁定? –
請參閱:http://stackoverflow.com/questions/920353/can-i-bind-an-array-to-an-in-condition/28067015#28067015 – Progrock
@ destination-data否,沒有錯誤。 – etilge