停止在第一次出現的字符

Question

我想只刪除「brealdeke」中的'a' 這個程序的工作原理是，它打印「breldeke」，但如果我把 「brealdeake」與2'a'字符串，它狂暴和打印：breldeakebrealdeke如何解決它？謝謝 我真的很想看看這個：

class Example { 
    public static String suppression(char c, String s) { 
     for (int i = 0; i < s.length(); i++) { 
      if (s.charAt(i) == c) { 
       int position = i; 
       for (int a = 0; a < position; a++) { 
        System.out.print(s.charAt(a)); 
       } 
       for (int b = position + 1; b < s.length(); b++) { 
        System.out.print(s.charAt(b)); 
       } 
      } 

     } 
     return ""; 
    } 

    public static void main(String[] args) { 
     // prints "breldeke" 
     System.out.println(suppression('a', "brealdeke")); 
     // prints "breldeakebrealdeke" 
     System.out.print(suppression('a', "brealdeake")); 
    } 
} 

Answer 1

附加變量好嗎？

我會做這樣的個人：

public static String removeFirstLetter(string s, char c) 
{ 
    String word = ""; 
    Bool foundChar = false; 

    for (int i = 0; i<s.length();i++) { 
     if (s.charAt(i).toLower() != c) 
     { 
     word += s.char(i); 
     } 
    else 
    { 
     if (foundChar == false){ 
      foundChar = true; 
     } 
     else 
     { 
      word += s.char(i); 
     } 
    } 
    } 
} 

System.out.print(word); 

Answer 2

你可以嘗試：

"banana".replaceFirst("a", ""); 

這將返回bnana

編輯：但願，這並不包括任何你還沒有被教過

public static void main(String[] args) { 
    String word = "banana"; 
    String strippedWord = ""; 
    boolean found = false; 
    for (int i = 0; i < word.length(); i++) { 
     if (word.charAt(i) == 'a' && !found) found = !found; 
     else strippedWord += word.charAt(i); 
    } 
    System.out.println(strippedWord); 
} 

這將打印bnana

EDIT2：你說你在一個函數想它，同樣適用：

public static String suppression(char c, String word) { 
    String strippedWord = ""; 
    boolean charRemoved = false; // This is a boolean variable used to know when the char was skipped! 
    for (int i = 0; i < word.length(); i++) { 
     // If the current letter is for example 'a' and we haven't yet skipped the char, skip this char we're at 
     if (word.charAt(i) == c && charRemoved == false) charRemoved = true; 
     else strippedWord += word.charAt(i); 
    } 
    return strippedWord; 
} 

public static void main(String[] args) { 
    // prints "breldeke" 
    System.out.println(suppression('a', "brealdeke")); 
    // prints "breldeake" 
    System.out.print(suppression('a', "brealdeake")); 
}