0
即時通訊編程新的編程,我只在PHP和Java編程,但我想了解更多的東西。 這可能不是最好的開始與音頻的東西,但我已經知道如何編程工作。Xcode Audiocomponent符號未找到,但無法使用的方法
但是,我想測試一下,從Apple網站獲取一些代碼,看看會發生什麼。 我在我的項目中粘貼了代碼的開頭,並且出現錯誤。我真的不知道他們的意思,搜索沒有給我任何結果。
那代碼:
#include <iostream>
#include <CoreAudio/CoreAudio.h>
#include <AudioToolbox/AudioToolbox.h>
#include <AudioUnit/AudioUnit.h>
int main(int argc, const char * argv[]) {
// insert code here...
AudioComponent comp;
AudioComponentDescription desc;
AudioComponentInstance auHAL;
//There are several different types of Audio Units.
//Some audio units serve as Outputs, Mixers, or DSP
//units. See AUComponent.h for listing
desc.componentType = kAudioUnitType_Output;
//Every Component has a subType, which will give a clearer picture
//of what this components function will be.
desc.componentSubType = kAudioUnitSubType_HALOutput;
//all Audio Units in AUComponent.h must use
//"kAudioUnitManufacturer_Apple" as the Manufacturer
desc.componentManufacturer = kAudioUnitManufacturer_Apple;
desc.componentFlags = 0;
desc.componentFlagsMask = 0;
//Finds a component that meets the desc spec's
comp = AudioComponentFindNext(NULL, & desc);
if (comp == NULL) exit(-1);
//gains access to the services provided by the component
AudioComponentInstanceNew(comp, & auHAL);
return 0;
}
,而這些都是錯誤的,我得到:
Undefined symbols for architecture x86_64:
"_AudioComponentFindNext", referenced from:
_main in main.o
"_AudioComponentInstanceNew", referenced from:
_main in main.o
ld: symbol(s) not found for architecture x86_64
clang: error: linker command failed with exit code 1 (use -v to see invocation)
感謝幫助我!