我有以下文件在我的收藏獲取使用MongoDB中找到
{
_id: ObjectId("5166fefbc482c31052000002"),
contact: [
{
home: 7735734105
},
{
office: 9583866301
}
],
user_name: "moti",
reportsTo: "bikram",
technology: [
{
name: ".net",
rating: 5
},
{
name: "JavaScript",
rating: 2
}
],
project: [
"Agile School",
"Draftmate"
],
type: "developer",
email: "[email protected]"
} 和
{
_id: ObjectId("5166fe90c482c31052000001"),
contact: [
{
home: 7735734103
},
{
office: 9583866901
}
],
user_name: "ganesh",
reportsTo: "bikram",
technology: [
{
name: "JavaScript",
rating: 3
},
{
name: ".net",
rating: 4
}
],
project: [
"SLBC",
"Draftmate"
],
type: "developer",
email: "[email protected]"
}
現在我需要找到誰認識的人的評價所需的輸出只有JavaScript.Currently if I run
db.users.find( { technology: { $elemMatch: { name: 'JavaScript' } } },{user_name:1,'technology.name':1,_id:0} ).pretty()
我得到所有技術的名稱(.net & JavaScript)及其相應的評級。我只需要用戶名,以及它們在JavaScript中的各自評分。我需要使用任何聚合技術嗎?
嘗試運行以下:db.users.find({技術:{$ elemMatch:{名稱: 'JavaScript的'}}},{USER_NAME:1 ,'technology。$。name':1,_id:0}) – 2013-04-11 20:45:38