在PHP中使用正則表達式將字符串轉換爲包含數字和字母表的數組？

Question

我有一個包含字母或數字的字符串。

AB1D21E48EFGHI1K 

我想將該字符串拆分爲數組，如下所示。

[0] => A 
[1] => B 
[2] => 1 
[3] => D 
[4] => 21 
[5] => E 
[6] => 48 
[7] => E 
[8] => F 
[9] => G 
[10] => H 
[11] => I 
[12] => 1 
[13] => K 

但是，我越來越陣列如下：

[0] => Array (
    [0] => AB 
    [1] => 1 
    [2] => D 
    [3] => 21 
    [4] => E 
    [5] => 48 
    [6] => EFGHI 
    [7] => 1 
    [8] => K 
) 

到目前爲止我嘗試下面的代碼。

$string = 'AB1D21E48EFGHI1K'; 
preg_match_all('/([0-9]+|[a-zA-Z]+)/', $string, $matches); 
print_r($matches); 

Answer 1

你應該字字符後刪除+與長度1匹配。所以，你的正則表達式應該是

/([0-9]+|[a-zA-Z])/ 

你可以讓你的正則表達式簡單

/\d+|\w/ 

代碼改爲

$string = 'AB1D21E48EFGHI1K'; 
preg_match_all('/\d+|\w/', $string, $matches); 
print_r($matches); 

檢查結果demo

Answer 2

請嘗試這樣的方式，它可能對你有用

<?php 
$data = array(0 => AB,1 => 1, 2 => D, 3 => 21, 4 => E, 5 => 48, 6 => EFGHI, 7 => 1, 8 => K); 

/*print "<pre>"; 
print_r($data); 
print "<pre>";*/ 


$new_data = array(); 
foreach($data as $key => $value){ 

    if (!preg_match('/[^A-Za-z]/', $value)) // '/[^a-z\d]/i' should also work. 
    { 
    // string contains only english letters 
    $arr1 = str_split($value); 
    foreach($arr1 as $row => $val){ 
     $new_data[] = $val; 
    } 
    }else{ 
    $new_data[] = $value; 
    } 

} 

/* 
print "<pre>"; 
print_r($new_data); 
print "<pre>";*/ 

?>