Python：如何從BaseHTTPRequestHandler HTTP POST處理程序獲取鍵/值對？

Question

給出了最簡單的HTTP服務器，我如何在BaseHTTPRequestHandler中獲得post變量？

from BaseHTTPServer import BaseHTTPRequestHandler, HTTPServer 

class Handler(BaseHTTPRequestHandler): 
    def do_POST(self): 
     # post variables?! 

server = HTTPServer(('', 4444), Handler) 
server.serve_forever() 

# test with: 
# curl -d "param1=value1&param2=value2" http://localhost:4444 

我只是想獲得param1和param2的值。謝謝！

Answer 1

def do_POST(self): 
    ctype, pdict = cgi.parse_header(self.headers.getheader('content-type')) 
    if ctype == 'multipart/form-data': 
     postvars = cgi.parse_multipart(self.rfile, pdict) 
    elif ctype == 'application/x-www-form-urlencoded': 
     length = int(self.headers.getheader('content-length')) 
     postvars = cgi.parse_qs(self.rfile.read(length), keep_blank_values=1) 
    else: 
     postvars = {} 
    ... 

Answer 2

我試圖編輯的帖子，結果被拒絕了，所以我的這個代碼，應該在Python 2.7版和3.2工作的版本：

from sys import version as python_version 
from cgi import parse_header, parse_multipart 

if python_version.startswith('3'): 
    from urllib.parse import parse_qs 
    from http.server import BaseHTTPRequestHandler 
else: 
    from urlparse import parse_qs 
    from BaseHTTPServer import BaseHTTPRequestHandler 

class RequestHandler(BaseHTTPRequestHandler): 

    ... 

    def parse_POST(self): 
     ctype, pdict = parse_header(self.headers['content-type']) 
     if ctype == 'multipart/form-data': 
      postvars = parse_multipart(self.rfile, pdict) 
     elif ctype == 'application/x-www-form-urlencoded': 
      length = int(self.headers['content-length']) 
      postvars = parse_qs(
        self.rfile.read(length), 
        keep_blank_values=1) 
     else: 
      postvars = {} 
     return postvars 

    def do_POST(self): 
     postvars = self.parse_POST() 
     ... 

    ...