如果我設置了具有附加標準約束的父級和子級關係的父/子關係,然後使用@JoinFetch,則childs additionalCriteria將被忽略。eclipselink在子類中被忽略的AdditionalCriteria
例如:
TableA.java:
@javax.persistence.Entity
@Table(name = "TABLE_A")
@AdditionalCriteria("this.tableAfield2=:propA")
public class TableA {
@Id
@Column(name = "TABLEAFIELD1")
private String tableAfield1;
@Column(name = "TABLEAFIELD2")
private String tableAfield2;
@JoinColumn(name = "TABLEAFIELD2", referencedColumnName = "TABLEBFIELD1", insertable = false, updatable = false)
@OneToOne(fetch = FetchType.EAGER)
// @JoinFetch(JoinFetchType.OUTER)
private TableB tableAtableB;
}
TableB.java:
@javax.persistence.Entity
@Table(name = "TABLE_B")
@AdditionalCriteria("this.tableBfield2=:propB")
public class TableB {
@Id
@Column(name = "TABLEBFIELD1")
private String tableBfield1;
@Column(name = "TABLEBFIELD2")
private String tableBfield2;
public String getTableBfield1() {
return tableBfield1;
}
public String getTableBfield2() {
return tableBfield2;
}
}
主要:
em.setProperty("propA", "propertyAValue");
em.setProperty("propB", "propertyBValue");
CriteriaBuilder cb = em.getCriteriaBuilder();
CriteriaQuery<TableA> criteriaQuery = cb.createQuery(TableA.class);
Root<TableA> tableA = criteriaQuery.from(TableA.class);
Predicate pred = cb.equal(tableA.get("tableAfield1"), "keyA1");
criteriaQuery.where(pred);
List<TableA> results = em.createQuery(criteriaQuery).getResultList();
隨着TABLEA設定爲每例(與JoinFetch註釋掉) 應用程序創建2個SQLS
SELECT TABLEAFIELD1, TABLEAFIELD2 FROM TABLE_A WHERE ((TABLEAFIELD1 = ?) AND (TABLEAFIELD2 = ?))
bind => [keyA1, propertyAValue]
SELECT TABLEBFIELD1, TABLEBFIELD2 FROM TABLE_B WHERE ((TABLEBFIELD1 = ?) AND (TABLEBFIELD2 = ?))
bind => [propertyAValue, propertyBValue]
這是很好的,的EclipseLink加載需求表-B。
但是對於我們的應用程序,我們需要有一個SQL,因爲可能有1000行,我們需要一個連接。
所以,如果我放回@JoinFetch那麼生成的SQL是;
SELECT t1.TABLEAFIELD1, t1.TABLEAFIELD2, t0.TABLEBFIELD1, t0.TABLEBFIELD2 FROM TABLE_A t1 LEFT OUTER JOIN TABLE_B t0 ON (t0.TABLEBFIELD1 = t1.TABLEAFIELD2) WHERE ((t1.TABLEAFIELD1 = ?) AND (t1.TABLEAFIELD2 = ?))
bind => [keyA1, propertyAValue]
不添加從表B的additionalCriteria(沒有t0.tableBField1 =?(propertyBValue))
任何建議?它讓我瘋狂。
非常感謝
爲了完整這裏是表
create table TABLE_A (
TABLEAFIELD1 varchar2(20),
TABLEAFIELD2 varchar2(30),
CONSTRAINT tableApk PRIMARY KEY (TABLEAFIELD1)
) ;
create table TABLE_B (
TABLEBFIELD1 varchar2(20),
TABLEBFIELD2 varchar2(30),
CONSTRAINT tableBpk PRIMARY KEY (TABLEBFIELD1)
) ;
insert into TABLE_A (TABLEAFIELD1,TABLEAFIELD2) values ('keyA1','propertyAValue');
insert into TABLE_A (TABLEAFIELD1,TABLEAFIELD2) values ('keyA2','propertyAValue');
insert into TABLE_A (TABLEAFIELD1,TABLEAFIELD2) values ('keyA3','random');
insert into TABLE_B (TABLEBFIELD1,TABLEBFIELD2) values ('propertyAValue','propertyBValue');
我發現了錯誤; https://bugs.eclipse.org/bugs/show_bug.cgi?id=438316這是超大型的,沒有感動。任何解決方法? –