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我有一個AJAX模式popupextender,我想使用Java腳本的一些處理後面的代碼年底顯現。我收到消息 錯誤:無法獲取未定義或空引用的屬性'show'。ModalPopupExtender顯示方法不從後臺代碼工作的JavaScript
<asp:Panel ID="panel1" runat="server" Visible="true" BorderColor="Black" Style="display: none">
<asp:UpdatePanel ID="uppanel1" runat="server">
<ContentTemplate>
<asp:Button ID="btn1" Text="Popup" Visible="true" runat="server" Style="display:none"/>
<ajaxToolKit:ModalPopupExtender ID="mpe1" runat="server" TargetControlID="btn1" PopupControlID="panel1" RepositionMode="None" PopupDragHandleControlID="drag1" BehaviorID="behave1"/>
<div id="div1" runat="server">
<asp:TextBox ID="txt1" runat="server" Text="Text" ></asp:TextBox>
</div>
</ContentTemplate>
</asp:UpdatePanel>
</asp:Panel>
function ShowPopUp(mpid) {
var id1 = $find(mpid);
id1.show();
}
歡迎SO!你能否爲你的答案提供一些解釋? – 2013-04-29 15:22:40