爲什麼Groovy會執行（）掛起？

Question

我有以下Groovy腳本：

#!/opt/groovy-1.8.6/bin/groovy 

final env = null // [] 

final command = ["./setter-for-catan.scala"] 
final process = command.execute(env, null) 

println (['echo', '********************** 0'].execute(env, null).text) 
final stdout = process.inputStream 
BufferedReader reader = new BufferedReader(new InputStreamReader(stdout)) 
while ((line = reader.readLine()) != null) { 
    System.out.println ("Stdout: " + line); 
} 

和以下的Scala腳本：

#!/bin/bash 

export SCALA_HOME=/opt/scala-2.10.1 

echo '********************* 1' "$0" "$@" 
${SCALA_HOME}/bin/scala -version 2>&1 
exec ${SCALA_HOME}/bin/scala "$0" "$@" 2>&1 
!# 

println("******************* 2") 

調用Groovy腳本輸出：

********************** 0 

Stdout: ********************* 1 ./setter-for-catan.scala 
Stdout: Scala code runner version 2.10.1 -- Copyright 2002-2013, LAMP/EPFL 
Stdout: ******************* 2 

如果env被定義爲[]，所述Groovy腳本掛起以下輸出：

********************** 0 

Stdout: ********************* 1 ./setter-for-catan.scala 
Stdout: Scala code runner version 2.10.1 -- Copyright 2002-2013, LAMP/EPFL 

發生了什麼事情以及需要做什麼以便​​不會掛起env是Array？

Answer 1

JAVA_HOME沒有被Scala腳本繼承，所以需要定義它。

一種方式做這將是在斯卡拉腳本：

#!/bin/bash 

export JAVA_HOME=/Library/Java/Home 
export SCALA_HOME=/opt/scala-2.10.1 

echo '********************* 1' "$0" "$@" 
${SCALA_HOME}/bin/scala -version 2>&1 
exec ${SCALA_HOME}/bin/scala "$0" "$@" 2>&1 
!# 

另一種方法是做到這一點的Groovy腳本：

final env = ['JAVA_HOME=/Library/Java/Home']