t-sql語句語法錯誤

Question

需要t-sql語句語法錯誤的幫助。按照以下完整陳述。 SQL服務器2005年

-- oitm to oitg is a 1 to 1 link via the 64 matching columns 
select g.[ItmsGrpNam], b.[ItmsGrpNam], count(1) 
from  oitg g 
    join (select distinct 
      i.ItmsGrpCod as [ItmsGrpCod], 
      i.QryGroup1 as [QryGroup1], 
      i.QryGroup2 as [QryGroup2] 
      from oitm i) p -- pseudo intersect table for oitg-oitm links 
    join oitb b on b.[ItmsGrpCod] = p.[ItmsGrpCod] 
where (g.ItmsGrpNam in -- translate interect to oitg names 
     (select x.ItmsGrpNam from oitg x where x.ItmsTypCod=1 and p.[QryGroup1]='Y') 
    ) 
group by g.ItmsGrpNam, b.ItmsGrpNam 

發現迄今在 使用SQLCMD。

select g.[ItmsGrpNam], b.[ItmsGrpNam], count(1) 
from  oitg g 
    join (select distinct 
      i.ItmsGrpCod as [ItmsGrpCod], 
      i.QryGroup1 as [QryGroup1], 
      i.QryGroup2 as [QryGroup2] 
      from oitm i) p -- pseudo intersect table for oitg-oitm links 
    join oitb b on b.[ItmsGrpCod] = p.[ItmsGrpCod] 

這部分的語句給出了以下錯誤。 Msg 102，Level 15，State 1，Server，Line 10 'ItmsGrpCod'附近語法不正確。

而上面的語句中的選擇將返回應有的樣子。

3> select distinct 
4>   i.ItmsGrpCod as [ItmsGrpCod], 
5>   i.QryGroup1 as [QryGroup1], 
6>   i.QryGroup2 as [QryGroup2] 
7>   from oitm i 
8> go 
ItmsGrpCod QryGroup1 QryGroup2 
---------- --------- --------- 
     100 N   N 
     101 N   Y 
     102 N   Y 
     103 N   Y 
     104 N   Y 
     105 N   Y 
     106 N   Y 
     107 N   N 
     108 N   N 
     108 Y   N 
     110 N   Y 
     111 N   N 
     112 N   Y 
     113 N   N 

嘗試用「內部連接」替換「連接」。已經開始用方括號括起列名。 ItmsGrpCod是oitm和oitb之間的fk，並且名稱相同。 （並不總是這種情況在SAP的土地！）

對於那些有興趣這是我的嘗試圍繞SAP B1設計缺陷的oitm（訂購商品） oitg（項目屬性）沒有相交表地獄。

Answer 1

您錯過了第一次加入的on聲明。也許是這樣的：

-- oitm to oitg is a 1 to 1 link via the 64 matching columns 
select g.[ItmsGrpNam], b.[ItmsGrpNam], count(1) 
from  oitg g 
    join (select distinct 
      i.ItmsGrpCod as [ItmsGrpCod], 
      i.QryGroup1 as [QryGroup1], 
      i.QryGroup2 as [QryGroup2] 
      from oitm i) p -- pseudo intersect table for oitg-oitm links 
     on g.ItmsGrpCod = p.ItmsGrpCod 
    join oitb b on b.[ItmsGrpCod] = p.[ItmsGrpCod] 
where (g.ItmsGrpNam in -- translate interect to oitg names 
     (select x.ItmsGrpNam from oitg x where x.ItmsTypCod=1 and p.[QryGroup1]='Y') 
    ) 
group by g.ItmsGrpNam, b.ItmsGrpNam 

Answer 2

你可以發佈這些表的模式嗎？ oitb是否有ItmsGrpCod列？ SQL Server對於糟糕的錯誤報告而言是相當臭名昭着的，但請注意，您在查詢中使用了四次ItmsGrpCod。