4
我使用jQuery在頁面加載時動態添加兩個div。這一切都很好,除了,當我點擊第一個動態加載的div中的「高級選項」鏈接 - 它執行正確的行爲(滑動第二個動態div),但它重置窗口的滾動回到頂部。我試圖專注於我滑開的div的第一個輸入元素,但無濟於事。如何防止窗口滾動jQuery slideToggle()?
我該如何擺脫這種不需要的滾動行爲?
我已經包括了代碼,以幫助(如長篇大論,因爲它是)
<style type="text/css">
.itemcontainer {
background-color:#FFFFCC;
border:1px solid #999999;
height:auto;
margin:1em 0;
overflow:hidden;
position:relative;
width:600px;
}
.itemcontainer .optionpopoutcontainer {
background-color:#44CC55;
bottom:0;
color:#333333;
height:auto;
left:0;
padding:6px;
position:absolute;
width:100%;
}
.itemcontainer .advancedpopoutcontainer {}
</style>
這裏是一個與HTML一起的JavaScript
<script type="text/javascript">
$(document).ready(function(){
var counter = 0;
//Add the necessary divs to the classes
$(".itemcontainer").each(function(){
var id = $(this).find("input[name='ItemID']").attr('value');
$(this).append("<div class='optionpopoutcontainer' id='quickaddcontainer-" + id + "'></div><div class='advancedpopoutcontainer' id='advancedaddcontainer-" + id + "'></div>");
});
$(".optionpopoutcontainer").css("display", "none"); //used for the sliding up
$(".optionpopoutcontainer").each(function(){
createQuickAddForm($(this), GetID($(this)));
});
$(".advancedpopoutcontainer").css("display", "none"); //used for the sliding up
$(".advancedpopoutcontainer").each(function(){
AddAdvancedOptionsForm($(this), GetID($(this)));
});
$(".cancelButton").click(function(){
var parent = GetParentDiv($(this));
parent.slideToggle();
});
$(".opencontainer").click(function(){
GetParentDiv($(this)).find("div.optionpopoutcontainer").slideToggle(250);
});
$(".quickaddadvoptions").click(function(){
var container = GetParentDiv($(this));
$(container).slideToggle(function(){
var innerContainer = GetParentDiv(container).find("div.advancedpopoutcontainer").slideToggle(250);
});
});
function GetParentDiv(item){
return item.parents('div:eq(0)');
}
function GetID(item){
return item.attr('id').split('-')[1];
}
$("input[name='Date']").each(function(){
$(this).datepicker({dateFormat: 'd MM, y'});
});
});
function createQuickAddForm(item, itemID){
var str = "<form method='post' action='#' id='addform-" + itemID + "'>";
str += "Size: <input id='Size' type='text' value='1' name='Size'/> ";
str += "<input id='ItemID' type='hidden' value='29' name='ItemID'/>";
str += "<input type='submit' value='Log Item'/>";
str += "<a href='#'' class='quickaddadvoptions' id='advancedoptions-" + itemID + "'>Advanced Options</a>";
str += "</form>";
str += "<button class='cancelButton'>Cancel</button>";
item.html(str);
};
function AddAdvancedOptionsForm(containerDiv, itemID){
var str = "<form method='post' action='#' id='addformadv-" + itemID + "'>";
str += "Size: <input id='Size-" + itemID + "' type='text' value='1' name='Size'/><br/>";
str += "Date: <input id='Date-" + itemID + "' type='text' value='" + GetTodaysDate() + "' name='Date'/><br/>";
str += "Note: <input type='textarea' id='Note-" + itemID + "' name='Note' cols='20' name='Note'/><br/>";
str += "<input id='ItemID-" + itemID + "' type='hidden' value='29' name='ItemID'/>";
str += "<input type='submit' value='Log Item'/>";
str += "</form>";
str += "<button class='cancelButton' >Cancel</button>";
containerDiv.html(str);
};
<div class="itemcontainer" name="item1">
<!-- <table> code -->
<button style="float:right" class="opencontainer">slide it</button>
<!-- other <table> code -->
<input type="hidden" value="2" name="ItemID"/>
</div>
不知道我是怎麼錯過的。謝謝,我感謝幫助。 – MunkiPhD 2009-09-08 04:08:01
或者更好的是,不要使用標籤來收集點擊事件。先生,你是個紳士和學者。 – Neil 2016-02-24 13:05:00