在相同的SQL查詢中選擇最大值和最小值

Question

我有一個SQL表，包含ID：ADate，XValue和Type。對於每個「Type」值，我想檢索最近的行（每ADate），最近的行（每ADate）以及包含最高「XValue」值的行。

是否可以通過單個SQL查詢執行？我嘗試了幾次，但沒有成功。

Answer 1

select ID, ADate, XValue,[Type] 
from (
    select * 
    ,row_number() over (partition by type order by adate asc) AS DateSeq 
    ,row_number() over (partition by type) AS TypeCount 
    ,row_number() over (partition by type order by xvalue desc) AS ValueSeq 
    from t 
) as tt 
where tt.DateSeq=1 OR tt.DateSeq=tt.TypeCount OR tt.ValueSeq=1 

Answer 2

使用row_number()你可以做這樣的事情：

select ID, ADate, XValue and Type 
from (
    select * 
    , min_adate = row_number() over (partition by type order by adate asc) 
    , max_adate = row_number() over (partition by type order by adate desc) 
    , max_xvalue = row_number() over (partition by type order by xvalue desc) 
    from t 
) as sub 
where 1 in (min_adate,max_adate,max_xvalue) 
/* --also could be written as 
where min_adate = 1 
    or max_adate = 1 
    or max_xvalue = 1 
*/ 

使用common table expression可能使其更具可讀性。

;with cte as (
    select * 
    , min_adate = row_number() over (partition by type order by adate asc) 
    , max_adate = row_number() over (partition by type order by adate desc) 
    , max_xvalue = row_number() over (partition by type order by xvalue desc) 
    from t 
) 
select ID, ADate, XValue and Type 
from cte 
where 1 in (min_adate,max_adate,max_xvalue) 

Answer 3

一種方法是使用row_number()：

select t.* 
from (select t.*, 
      row_number() over (partition by type order by aDate desc) as seqnum_adate_desc, 
      row_number() over (partition by type order by aDate asc) as seqnum_adate_asc, 
      row_number() over (partition by type order by XValue desc) as seqnum_xvalue_desc 
     from t 
    ) t 
where 1 in (seqnum_adate_desc, seqnum_adate_asc, seqnum_xvalue_desc);