MySQL的/ PHP的樹導航菜單

Question

代碼輸出需要：

視頻輸出：

我的SQL數據庫 'test'

CREATE TABLE IF NOT EXISTS `menu` (
    `id` int(11) NOT NULL AUTO_INCREMENT, 
    `name` varchar(50) NOT NULL, 
    `link` varchar(100) NOT NULL, 
    `parrent_id` int(11) NOT NULL DEFAULT '0', 
    `status` varchar(4) NOT NULL, 
    PRIMARY KEY (`id`) 
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=11 ; 

-- 
-- Dumping data for table `menu` 
-- 

INSERT INTO `menu` (`id`, `name`, `link`, `parrent_id`, `status`) VALUES 
(1, 'Home', '#home', 0, 'Show'), 
(2, 'About', '#about', 0, 'Show'), 
(3, 'Our services', '#service', 0, 'Show'), 
(4, 'Get involved', '#getinvolved', 0, 'Show'), 
(5, 'Donors', '#donors', 0, 'Show'), 
(6, 'News', '#news', 0, 'Show'), 
(7, 'Contact Us', '#contact', 0, 'Show'), 
(8, 'Ourselves', '#ourselves', 2, 'Show'), 
(9, 'Objectives', '#objectives', 2, 'Show'), 
(10, 'Our Patrons', '#patrons', 2, 'Show'); 

我的PHP代碼在這裏....

<?php 
    $dbuser="root"; 
    $dbpass=""; 
    $dbname="test"; //the name of the database 
    $chandle = mysql_connect("localhost", $dbuser, $dbpass) 
    or die("Connection Failure to Database"); 
    mysql_select_db($dbname, $chandle) or die ($dbname . " Database not found. " . $dbuser); 

    function menu($parrent) { 
    echo "<ul>"; 
    $sql = "SELECT * from menu where parrent_id=".$parrent; 
    while($res = mysql_fetch_array(mysql_query($sql))) 
    echo "<li><a href='".$res['link']."'>".$res['name']."</a></li>"; 
    echo "</ul>"; 
    } 
    $sql = "SELECT * from menu where parrent_id =0"; 
    echo "<ul>"; 
    while($resnew = mysql_fetch_array(mysql_query($sql))) 
    { 
    $sql_sub = "SELECT * from menu where parrent_id=".$resnew['id']; 
    $count = mysql_num_rows(mysql_query($sql_sub)); 
    if($count>0) 
    { 
     echo "<li><a href='".$resnew['link']."'>".$resnew['name']."</a>"; 
     menu($resnew['id']); 
     echo "</li>"; 
    } 
    else 
    { 
     echo "<li><a href='".$resnew['link']."'>".$resnew['name']."</a></li>"; 
    } 
    } 
    echo "</ul>"; 
?> 

Answer 1

菜單樹

a。創建表「categorylist」。

CREATE TABLE IF NOT EXISTS `categorylist` (
`id` int(5) NOT NULL auto_increment, 
`cname` varchar(25) collate utf8_unicode_ci default NULL, 
`pid` int(5) NOT NULL, 
`url` text collate utf8_unicode_ci, 
`status` int(1), 
PRIMARY KEY (`id`), 
KEY `pid` (`pid`) 
) ENGINE=MyISAM DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci AUTO_INCREMENT=9 ; 

---

灣在 「所屬分類」

INSERT INTO `categorylist` (`id`, `cname`, `pid`, `url`, `status`) VALUES 
(1, 'Entertainment', 0, '#',1), 
(2, 'Movies', 1, 'http://example.com/movie.php',1), 
(3, 'Drama', 1, 'http://example.com/drama.php',1), 
(4, 'Sports', 0, '#',1), 
(5, 'Football', 4, 'http://example.com/football.php',1), 
(6, 'Cricket', 4, 'http://example.com/cricket.php',1), 
(7, 'Politics', 0, '#',1), 
(8, 'Politics news', 7, 'http://example.com/politics-news.php',1); 

---

c裝入值。樣式表

.nav ul li { background:#f1f1f1; list-style: none;} 
ul.dropdown { position:relative; width:auto; font:12px Arial, Helvetica, sans-serif; } 
ul.dropdown li { float:left; zoom:1; height:30px; padding:6px 2px 0 2px; } 
ul.dropdown li li { border-right:1px solid #ccc; border-left:1px solid #ccc; margin-left:-30px;} 
ul.dropdown a:hover { color:#000; } ul.dropdown a:active { color:#ffa500; } 
ul.dropdown li a { display:block; padding:4px 8px; color:#000; text-decoration:none; font:bold 12px Arial, Helvetica, sans-serif; } 
ul.dropdown li:last-child a { border-right:none;} /* Doesn't work in IE */ 
ul.dropdown li:hover { color:#000; background:#e7e7e7; position:relative; } 
ul.dropdown li.hover a { color:#000; } 
ul.dropdown ul { text-align:left; visibility: hidden; position: absolute; left:-10px; top:36px; } 
ul.dropdown ul li { background:#f1f1f1; border-bottom:1px solid #ccc; float:none; width:120px; height:25px; } 
ul.dropdown ul li a { border-right:none; width:100%; display:inline-block; color:#000; } 
ul.dropdown ul ul { left:100%; top:0; } 
ul.dropdown li:hover > ul { visibility:visible; } 

---

d。菜單腳本代碼

<?php 

$con=mysql_connect("localhost", "root", "") or die('Server connexion not possible.'); 
mysql_select_db("newone",$con) or die('Database connexion not possible.'); 

$qry="SELECT * FROM categorylist" where status=1; 
$result=mysql_query($qry,$con); 


$arrayMenu = array(); 

while($row = mysql_fetch_assoc($result)){ 
$arrayMenu[$row['id']] = array("pid" => $row['pid'], "name" => $row['cname'], "url" => $row['url']); 
} 


//createTree($arrayCategories, 0); 

function createTree($array, $curParent, $currLevel = 0, $prevLevel = -1) { 

foreach ($array as $categoryId => $category) { 

if ($curParent == $category['pid']) { 

if($category['pid']==0) $class="dropdown"; else $class="sub_menu"; 
if ($currLevel > $prevLevel) echo " <ul class='$class'> "; 


if ($currLevel == $prevLevel) echo " </li> "; 

echo '<li id="'.$categoryId.'" >&lt;a href="'.$category['url'].'"&gt;'.$category['name'].'&lt;/a&gt;'; 

if ($currLevel > $prevLevel) { $prevLevel = $currLevel; } 

$currLevel++; 

createTree ($array, $categoryId, $currLevel, $prevLevel); 

$currLevel--; 
} 
</pre> 
} 

if ($currLevel == $prevLevel) echo " </li> </ul> "; 

} 
?> 

<div class="nav"> 

<?php 
if(mysql_num_rows($result)!=0) 
{ 
php createTree($arrayMenu, 0); 
} 
?> 
</div> 

Answer 2

嘗試此查詢這就是所謂的半加盟

select 
    l.id, 
    l.name, 
    group_concat(r.name) 
from menu l 
inner join menu r 
on r.parrent_id = l.id 
group by l.name 

你也可以提供一個where條件可以根據自己的需求在這裏它會帶來所有的結果，如果家長ID不是0獲得滿意的結果。 如何使用Group Concat值 使用php explode函數來執行此操作。

Answer 3

這個我一直用Kohana框架中的ORM編碼。也許它有幫助。如果沒有，請隨時得到啓發...

public function roleTree(){ 
    // find topmost nodes 
    $roles = ORM::factory('Role')->where('parent_id', '=', '0')->find_all(); 
    $nodes = array('node' => NULL, 'depth' => 0, 'childs' => array()); 
    foreach($roles as $role){ 
     $nodes['childs'][] = array('node' => $role, 'depth' => 1, 'childs' => $this->_roleTree($role, 1)); 
    } 
    return $nodes; 
} 

private function _roleTree($role, $depth){ 
    // add child nodes 
    $depth ++; 
    $roles = ORM::factory('Role')->where('parent_id', '=', $role->id)->find_all(); 
    $nodes = array(); 
    if(count($roles)){ 
     foreach($roles as $role){ 
      $nodes[] = array('node' => $role, 'depth' => $depth, 'childs' => $this->_roleTree($role, $depth)); 
     } 
     return $nodes; 
    } 
    return array(); 
} 

它創建一個結構化的幻想，但簡單的數組...