的MySQL Where子句錯誤

Question

我有下面的語句

$result = mysql_query("SELECT * from rests ORDER BY name asc WHERE flag = '1' LIMIT 0 , 20"); 

正在以下錯誤

Invalid query: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'WHERE flag = '1' LIMIT 0 , 20' at line 1 

我不知道我要去哪裏錯了:(

Answer 1

你不能有ORDER BY條款WHERE條款

請參考MySQL select syntax爲各個子句的正確順序。

試試這個：

SELECT * from rests WHERE flag = '1' ORDER BY name asc LIMIT 0 , 20 

升序排序也就是默認情況下，你可能會下降的asc。

Answer 2

$result = mysql_query("SELECT * from rests WHERE flag = '1' ORDER BY name asc LIMIT 0 , 20"); 

Answer 3

WHERE在ORDER BY之前。

Answer 4

ORDER BY子句必須在WHERE子句之後。就是這樣。

Answer 5

ORDER BY在最後的WHERE和LIMIT之後。