2017-08-17 50 views
0

我爲sqlite3操作編寫了兩個腳本。在我的第一個腳本中,我創建了數據庫和表名。在第二個腳本中,我創建了表記錄。在執行第二個腳本時,我想要獲取已創建的數據庫並選擇表名稱..請任何人幫助我..!我如何獲取已創建的數據庫和腳本中的表。

script1.sh

#!/bin/bash 

echo " --- Enter the Database name ---" #name of the database 
read databasename 

echo " --- enter the table name --- " #name of the table 
read table_name 

sqlite3 $databasename.db "DROP TABLE IF EXISTS $table_name;" 

sqlite3 $databasename.db "CREATE TABLE IF NOT EXISTS $table_name(cus_id INTEGER PRIMARY KEY AUTOINCREMENT UNIQUE,cus_name TEXT NOT NULL UNIQUE ,cus_domain TEXT UNIQUE, cus_status TEXT NOT NULL,Port INTEGER NOT NULL);" #table creation 

Script2.sh

echo "choose the database" 
#Here i want to choose the already create database. 

echo "choose the table" 
#Here i want to choose the table in the alreadt created database. 

echo " --- Enter the total number of customer records do you want ---" 
read cus_count # number of rows value 


echo "--- Enter the following details one by one---" 

RED='\033[0;31m' 
NC='\033[0m' 
port_num=8080 
declare -a customer 

for((i=1;i<=cus_count;i++)) 
do 


echo "enter the $i customer details" 

echo "---Enter the customer name---" 
read c_name 

d_name=${c_name,,} 
#echo $d_name 

customer=$(sqlite3 $databasename.db "select cus_domain from $table_name where cus_domain like '$d_name';") 

for cus in "${customer[@]}" 
do 

if [[ $d_name != $customer ]]; 

then 
    echo "---Enter the Status(Active/Inactive)---" 
    read c_status 

if [[ "$port_num" == "$port_num" ]]; then 
     port_num=$(($port_num + 1)) 

c_domain="$c_name" 


sqlite3 $databasename.db "INSERT OR IGNORE INTO $table_name (cus_name,cus_domain,cus_status, Port) VALUES(\"$c_name\",\"${c_domain,,}\",\"${c_status,,}\",\"$port_num\") ;" 
fi 


else 
    echo -e "${RED}!!!OOPS for you entered customer name already domain name assigned!!!${NC}" 
    echo -e "${RED}Please enter new customer name${NC}" 

i=$(($i - 1)) 

fi 
done 
done 

echo " --- Records from the $table_name ---" 

sqlite3 $databasename.db "select * from $table_name;" 

請提前任意一個幫助me..Thanks ...

+0

如何寫表名的文件中的第一個腳本'echo -n $ table_name> table_name.txt'並在第二個'table_name = $(cat table_name.txt)' –

+0

中選擇ok.but如何選擇數據庫... ? – Mahendranatarajan

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將數據庫名稱寫入第二個文件。或者首先將數據庫名稱寫入文件,然後在同一個文件中追加表名? –

回答

0

您可以編寫數據庫和表名一份文件。

echo $databasname >> /tmp/new_database 
echo $table >> /tmp/new_database 

和配置第二個腳本讀取這個文件

或者你可以從腳本一個通過數據庫名和表名作爲ARGS調用腳本2

script1 
#!/bin/bash 

... 
/bin/bash script2.sh $databasename $tablename 


script2.sh 
#!/bin/bash 
databasename = $1 
tablename = $2 
+0

sqlite3 $ databasename.db「DROP TABLE IF EXISTS $ table_name;」在上述查詢我不想DROP操作。我可以爲它做些什麼..? – Mahendranatarajan

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查看詳細信息[here](https://stackoverflow.com/a/9565901/4175515),但這是表創建 –

+0

中的常見聲明我不想刪除我的表。我希望我的表格數據可用於下一步操作 – Mahendranatarajan

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