MySQL的排序一個表

Question

的兩列我有這個表：

CREATE TABLE table_name (id INT, for_id INT, comms VARCHAR(50)); 
    INSERT INTO table_name VALUES (1,0, 'boo'), 
            (2,1, 'John'), 
            (3,0, 'Zoe'), 
            (4,3, 'bar'), 
            (5,1, 'Don'), 
            (6,3, 'FOO'), 
            (7,1, 'Doe'); 

http://sqlfiddle.com/#!9/859933/6

我怎樣才能得到下一個：

1.0.'boo' 
2.1.'John' 
5.1.'Don' 
7.1.'Doe' 
3.0.'Zoe' 
4.3.'bar' 
6.3.'FOO' 

謝謝！

Answer 1

不知道這是什麼，你到底要還是沒有，你應該做的崗位，結果爲了一些解釋。

select * 
from table_name 
order by 
    case when for_id = 0 then concat(id, for_id) + 0 
     else concat(for_id, id) + 0 
    end 

and SQLFiddle Demo Here。

更新時間：

再試下，

select * 
from table_name 
order by 
    case when for_id = 0 then mod(concat(for_id, id) + 0, 10) 
     else mod(concat(id, for_id) + 0, 10) 
    end 
    , id asc 

SQLFiddle

再次更新：

select * 
from table_name 
order by 
    case when for_id = 0 then id 
     else for_id 
    end 
    , id asc 

SQLFiddle

Answer 2

只需使用order by，它可以通過獲得超過一場

Select * from table_name 
    order by id asc, for_id asc; 

Answer 3

使用秩序和Cancat

select Concat(id,'.',for_id) as id ,comms 
from table_name 
order by id asc,for_id asc 

更新時間：

使用order by和應用case語句根據您的情況而定

select * 
from table_name 
order by 
    case when for_id = 0 then concat(id, for_id) + 1 
     else concat(for_id, id) + 0 
    end 

http://sqlfiddle.com/#!9/859933/25