使用字符串方法在java中使用第一個和最後一個字母

Question

我是java的初學者，我們被要求使用大寫字母的第一個和最後一個字母。

[提示：捕獲信作爲字符串（使用的子方法），然後使用toUpperCase（）方法]

所有我到目前爲止是這樣的，

import java.util.Scanner; 

public class Excercise6 { 
    public static void main (String [] args){ 

    Scanner keyboard = new Scanner (System.in); 
    System.out.print("Please Type a word: "); 
    String word = keyboard.nextLine(); 

    int stringLength = word.length(); 
    String letter1 = word.substring (0,1); 
    String lastletter = word.substring ((stringLength-1),(stringLength)); 
    String newWord =letter1.toUpperCase() + lastletter.toUpperCase(); 


    System.out.println("The word with first letter capitalized is: " + newWord); 

    } 
} 

我如何在第一個和最後一個字母之間添加單詞？

Answer 1

代碼看起來很好，只是做一些改變

String newWord = letter1.toUpperCase() 
       + word.substring(1, word.length() - 1) 
       + lastletter.toUpperCase(); 

第一個字母 - letter1.toUpperCase()

中東字符串 - word.substring(1, word.length() - 1)

最後一個字母 - lastletter.toUpperCase();

輸出

Please Type a word: ankur 
The word with first letter capitalized is: AnkuR 

Answer 2

你可以嘗試以下

String letter1 = word.substring (0,1); 
String lastletter = word.substring ((stringLength-1),(stringLength)); 
String newWord =letter1.toUpperCase() + word.subString(1, stringLength-1) + lastletter.toUpperCase(); 

這應該給你的這個詞的「中間」，而第一個和最後一個字母

Answer 3

嘗試是這樣的：

String a = "java"; 
String first = a.substring(0, 1).toUpperCase(); 
String last = a.substring((a.length() - 1), a.length()).toUpperCase(); 
String middle = a.substring(1, a.length() - 1); 
System.out.println(first + middle + last); 

Answer 4

在S特林。 substring()方法會給你一個子串。所以，這個詞分成幾部分，就像你做了部分 -

String startChar = word.substring(0, 1); 
String endChar = word.substring(word.length()-1); //If you leave out the last argument, it goes all the way to the end of the String 
String middle = word.substring(1, word.length()-1); 

然後，只需建立自己的新詞（第一個字符，再加上中間部分，加上最後一個字符）並轉換相關部分加時賽上的情況下使用String 。 upperCase()方法

String newWord = startChar.toUpperCase() + middle + endChar.toUpperCase(); 

Answer 5

你可以簡單地做

String st="singhakash"; 
System.out.println(st.substring(0,1).toUpperCase()+st.substring(1,st.length()-1)+st.substring(st.length()-1).toUpperCase()); 

輸出

SinghakasH 

DEMO

Answer 6

由於大家都把一個建議，將工作;我正在調整一個更有效和安全的建議。

String word = keyboard.nextLine(); 

這不保證一個字。它返回一行，這意味着換行符「\ n」之前的任何內容。

要得到的話，你應該使用：

String[] words = keyboard.nextLine().split(new char[] { ' ', '\t', '\r' }); 

這將拆分上的字符行：空格，製表符和回車（注：不換行）。

接下來我們通過每一個字需要循環使用for-each循環：

for(String word : words) 
{ 
int wordLength = word.length(); // Get length, because we're gonna use  it multiple times 
if(wordLength > 0) // Ignore empty words 
{ 
    // Only get the first character and convert it to uppercase (better than using substring) 
    // Also note that we don't have to check if there's a character at 0, because we already did with wordLength > 0 
    char firstCharacter = Character.toUpperCase(word.charAt(0)); 

    StringBuilder builder = new StringBuilder(firstCharacter); // We use StringBuilder class because it is efficient in concatenating objects to a string 

    if(wordLength == 2) // We only got 2 characters, so no inbetween 
    { 
     char lastCharacter = Character.toUpperCase(word.charAt(1)); // We know this character is at index 1 

     builder.append(lastCharacter); // Append last character 
    } 
    else // More than 2 
    { 
     String inbetweenCharacters = word.substring(1, wordLength - 2); // Get the words in between using substring 
     char lastCharacter = Character.toUpperCase(word.charAt(wordLength - 1)); // Get the last character 

     builder.append(inbetweenCharacters); // Append inbetween characters 
     builder.append(lastCharacter); // Append last character 
    } 

    System.out.println(builder.toString()); // Print complete converted word 
} 
} 

我這樣做對我的頭頂，我希望這不會有任何錯別字

Answer 7

/**代碼添加字符串句的第一個到最後一個，第二個到第二個，第三個到第三個最後一個和 作者：deependra singh patel */

import java.util.Scanner;

公共類ReverseStringWordConcate {

public static void main(String[] args) { 
    Scanner scn = new Scanner(System.in); 
    System.out.println("Enter The Sentence"); 
    String s1 = scn.nextLine(); 
    String []s2 = s1.split(" "); 
    int i1 = 0; 
    for(int i =s2.length-1;i>=0;i--) { 
     if(s2[i]==s2[i1]){ 
      char [] arr = s2[i].toCharArray(); 
      System.out.print(arr.length+s2[i1]); 
      break; 
     } 
     else { 
     //System.out.print(s2[i]+s2[i1]+" "); 
     char [] arr = s2[i].toCharArray(); 
     char arr1[] = s2[i1].toCharArray(); 
     System.out.print((arr.length+arr1.length)+s2[i]+s2[i1]+" "); 

     } 
     i1++; 
} 






} 
} 

/*樣品輸入：deependra辛格巴特爾thegun singhraur

expected output :18singhraurdeependra 11thegunsingh 5patel  

*/