從當前日期起30天內查詢MySql數據庫的'生日'日期字段

Question

我想寫一個查詢MySql數據庫並返回生日日期字段在未來30天內的條目的PHP腳本。我能夠做到這一點，但是我需要在進行查詢時從生日日期中排除年份。例如，如果今天的日期是2013年7月7日，並且所涉及的生日是7/13/1991，顯然這兩個日期相距超過30天，但如果我們排除這一年，它們只相隔3天。使這個有效的生日返回。

生日字段作爲DATE存儲在MySql數據庫中。

到目前爲止，我所做的查詢：

$results = mysql_query("SELECT * FROM Club WHERE Birthday < DATE_SUB(NOW(), INTERVAL 30 DAY)"); 

我能做些什麼來修改這個查詢不採取今年考慮？

Answer 1

這是你在找什麼？

SELECT * FROM Club WHERE month(Birthday) = month(DATE_SUB(NOW(), INTERVAL 30 DAY)) and dayofmonth(Birthday) = dayofmonth(DATE_SUB(NOW(), INTERVAL 30 DAY));

http://pastebin.com/uEXrXrHT

Answer 2

我沒有測試過，但我認爲這會做，從閱讀很清楚它做什麼。

SELECT * FROM Club WHERE DAYOFYEAR(Birthday) BETWEEN DAYOFYEAR(NOW()) AND DAYOFYEAR(NOW()) + 30; 

Answer 3

設置你的窺視，確定他們的下一個出生日期（可以在下一個日曆年），顯示在未來30天有生日的人。工作在一年包裝（在12月）結束，等

http://sqlfiddle.com/#!2/d881b/4

create table peeps 
(id int not null auto_increment, 
    lastname varchar(40) not null, 
birthdate datetime not null, 
primary key (id) 
); 

insert peeps (lastname,birthdate) values ('sam', '1973-01-01'); 
insert peeps (lastname,birthdate) values ('julie', '1973-02-01'); 
insert peeps (lastname,birthdate) values ('kim', '1973-03-01'); 
insert peeps (lastname,birthdate) values ('fred', '1973-04-01'); 
insert peeps (lastname,birthdate) values ('oscar1', '1973-05-01'); 
insert peeps (lastname,birthdate) values ('oscar2', '1973-05-02'); 
insert peeps (lastname,birthdate) values ('oscar3', '1973-05-04'); 
insert peeps (lastname,birthdate) values ('oscar4', '1973-05-06'); 
insert peeps (lastname,birthdate) values ('oscar5', '1973-05-08'); 
insert peeps (lastname,birthdate) values ('oscar6', '1973-05-10'); 
insert peeps (lastname,birthdate) values ('oscar7', '1973-05-12'); 
insert peeps (lastname,birthdate) values ('oscar8', '1973-05-14'); 
insert peeps (lastname,birthdate) values ('oscar9', '1973-05-16'); 
insert peeps (lastname,birthdate) values ('oscar10', '1973-05-18'); 
insert peeps (lastname,birthdate) values ('oscar11', '1973-05-20'); 
insert peeps (lastname,birthdate) values ('oscar12', '1973-05-22'); 
insert peeps (lastname,birthdate) values ('oscar13', '1973-05-24'); 
insert peeps (lastname,birthdate) values ('Felix the Cat1', '1973-06-01'); 
insert peeps (lastname,birthdate) values ('Felix the Cat2', '1973-06-05'); 
insert peeps (lastname,birthdate) values ('Felix the Cat3', '1973-06-07'); 
insert peeps (lastname,birthdate) values ('Bonehead7', '1973-07-01'); 
insert peeps (lastname,birthdate) values ('Bonehead8', '1973-08-01'); 
insert peeps (lastname,birthdate) values ('Bonehead9', '1973-09-01'); 
insert peeps (lastname,birthdate) values ('Bonehead10', '1973-10-01'); 
insert peeps (lastname,birthdate) values ('Bonehead11', '1973-11-01'); 
insert peeps (lastname,birthdate) values ('Bonehead12', '1973-12-01'); 

create table peeps_next_birthday 
(id int not null, 
next_birthdate datetime not null 
); 

insert into peeps_next_birthday (id,next_birthdate) select id,birthdate from peeps; 


UPDATE peeps_next_birthday set next_birthdate=date_add(next_birthdate, interval (year(curdate())-year(next_birthdate)) year); 

update peeps_next_birthday set next_birthdate=date_add(next_birthdate,interval 1 year) 
where curdate()>next_birthdate; 

    /// *************************** now show the birthdays in the coming 30 days 

select t2.id,t2.lastname,t1.next_birthdate 
from peeps_next_birthday t1 
join peeps t2 
on t2.id=t1.id 
where datediff(t1.next_birthdate,curdate())<=30 

Answer 4

這是一個有點棘手，但這裏是我的解決方案：

SELECT 
    birthday, 
    -- Shift the birthday into the current year 
    CAST(CONCAT(YEAR(NOW()), '-', MONTH(birthday), '-', DAY(birthday)) AS DATE) AS BirthdayInCurrentYear 
FROM Club 
WHERE CAST(CONCAT(YEAR(NOW()), '-', MONTH(birthday), '-', DAY(birthday)) AS DATE) 
    BETWEEN NOW() AND NOW() + INTERVAL 30 DAY; 

此查詢的工作與閏年，並在下一年的日期。您可以使用我的SQLFiddle進行測試和驗證。

這可能不是最快的解決方案，因爲它會創建一個VARCHAR並將其解析回DATETIME。不幸的是，我沒有找到一個更好的方式，只有一個DATETIME的一年的一部分。