混淆的Javascript屬性訪問

Question

我不完全得到這個：

var one = {}; 
var two = {}; 
var three = {}; 

three[one] = "one"; 
three[two] = "two"; 

console.log(three[one]); // Alerts "two" 

據我瞭解，JS需要支架財產符號內的字符串。所以它看起來像JS正試圖改變：

three[one] = "one"; 
three[two] = "two"; 

到：

three[one.toString()] = "one"; 
three[two.toString()] = "two"; 

兩者的toString（）方法沒有定義，使他們最終會被相同的值？ 不知道我是否得到它。

Answer 1

其實toString方法的定義和結果在兩個相同的字符串（[object Object]）。

var one = {}; 
 
var two = {}; 
 
$('body').append(one.toString()+'<br>'+two.toString());

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

Answer 2

var one = {}; 
var two = {}; 
var three = {}; 

three[one] = "one"; 
three[two] = "two"; 

最後兩行說：

three[object] = "one"; 
three[object] = "two"; 

因爲一，兩個都聲明爲對象。

你正在做的三個對象將是這樣的：

[object Object] { 
    [object Object]: "two" 
}