python codeacademy發送一封信

我想教自己Python開始codeacademy的課程，到目前爲止它一直好。然而，我在學生成爲教師7/9時遇到了困難。我無法找到討論這個問題的線索，但是如果我錯過了一個，請隨時讓我知道。python codeacademy發送一封信

根據codeacademy我成功完成了這個練習，但我知道這段代碼有問題。當我在repl.it中使用下面的代碼時，get_average（student）會返回正確的值。我已經通過稍微改變成績進行了測試 - 但get_letter_grade（分數）爲每個學生返回「A」。我試着對允許的數字範圍進行更具體的描述（見下文），但我仍然有同樣的問題。

lloyd = { 
     "name": "Lloyd", 
     "homework": [90.0, 97.0, 75.0, 92.0], 
     "quizzes": [88.0, 40.0, 94.0], 
     "tests": [75.0, 90.0] 
    } 
alice = { 
     "name": "Alice", 
     "homework": [100.0, 92.0, 98.0, 100.0], 
     "quizzes": [82.0, 83.0, 91.0], 
     "tests": [89.0, 97.0] 
    } 
tyler = { 
     "name": "Tyler", 
     "homework": [0.0, 87.0, 75.0, 22.0], 
     "quizzes": [0.0, 75.0, 78.0], 
     "tests": [100.0, 100.0] 
    } 

def average(numbers): 
     total = sum(numbers) 
     total = float(total)/len(numbers) 
     return total 

def get_average(student): 
     homework = average(student["homework"]) 
     quizzes = average(student["quizzes"]) 
     tests = average(student["tests"]) 
     studentaverage = (homework * .1 + quizzes * .3 + tests *.6) 
     return studentaverage 

def get_letter_grade(score): 
    if score >= 90: 
     return "A" 
    elif score >= 80: 
     return "B" 
    elif score >= 70: 
     return "C" 
    elif score >= 60: 
     return "D" 
    else: 
     return "F"

我也試圖改變get_letter_grade（分數）的作用有點，使其更加具體的/受限制的（我可能會想走錯了路，我很新在這），如下：

def get_letter_grade(score): 
     if score >= 90: 
      return "A" 
     elif score >= 80 and score < 90: 
      return "B" 
     elif score >= 70 and score < 80: 
      return "C" 
     elif score >= 60 and score < 70: 
      return "D" 
     else: 
      return "F"

但如上所述，我有同樣的問題：無論我如何改變他們的成績，它都會爲每個學生返回「A」。

任何意見，見解，智慧等你關心分享將非常感激！

謝謝！

來源

2016-11-23 user7201984

你在哪裏使用'get_letter_score'功能？ – rassar

我試過上面的代碼，它沒有任何改變就能很好地工作。也許如果你可以分享你調用函數的方式，我可以對你可能一直遵循的錯誤程序進行闡述。下面是代碼片段及其相應的輸出。

lloyd = { 
     "name": "Lloyd", 
     "homework": [90.0, 97.0, 75.0, 92.0], 
     "quizzes": [88.0, 40.0, 94.0], 
     "tests": [75.0, 90.0] 
    } 
alice = { 
     "name": "Alice", 
     "homework": [100.0, 92.0, 98.0, 100.0], 
     "quizzes": [82.0, 83.0, 91.0], 
     "tests": [89.0, 97.0] 
    } 
tyler = { 
     "name": "Tyler", 
     "homework": [0.0, 87.0, 75.0, 22.0], 
     "quizzes": [0.0, 75.0, 78.0], 
     "tests": [100.0, 100.0] 
    } 

def average(numbers): 
     total = sum(numbers) 
     total = float(total)/len(numbers) 
     return total 

def get_average(student): 
     homework = average(student["homework"]) 
     quizzes = average(student["quizzes"]) 
     tests = average(student["tests"]) 
     studentaverage = (homework * .1 + quizzes * .3 + tests *.6) 
     return studentaverage 

def get_letter_grade(score): 
    if score >= 90: 
     return "A" 
    elif score >= 80: 
     return "B" 
    elif score >= 70: 
     return "C" 
    elif score >= 60: 
     return "D" 
    else: 
     return "F" 

# To calculate the grades of each student 
grade_tyler = get_letter_grade(get_average(tyler)) 
grade_lloyd = get_letter_grade(get_average(lloyd)) 
grade_alice = get_letter_grade(get_average(alice)) 

print(grade_lloyd) 
print(grade_alice) 
print(grade_tyler)

輸出：

乙

甲

另外我還試圖單獨地調用方法並如預期的結果。

grade_A = get_letter_grade(95) 
grade_B = get_letter_grade(85) 
grade_C = get_letter_grade(75) 
grade_D = get_letter_grade(65) 

print(grade_A) 
print(grade_B) 
print(grade_C) 
print(grade_D)

輸出：

甲

乙

來源

2016-11-23 21:16:02

python codeacademy發送一封信

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