0
let userModel = sequelize.define('userModel',{
//Schema
},{
//options
instanceMethods:{
checkPassword(){}
}
})
.........
async Login(){
let ins = await userModel.findOne('xxx')
ins.checkPassword // <= is not a function
}
看來該實例方法沒有加載到userModel.prototype
上。而我的console.log(ins)
,checkPassword
存在於屬性instanceMethods
中。無法獲取續集實例方法
如何調用instanceMethods?
sequelize版本:4.11.1
它工作時,我寫了''userModel.prototype.checkPassword''。那麼選項''instanceMethods''如何工作? – seeLuck