查找並替換紅寶石，除了一些短語文本文件

Question

我很確定我錯了。但我希望這個程序能夠通過「phone_numbers.txt」運行，並取代除["Employee Marked Urgency as: low", "Employee Marked Urgency as: high"]之外的任何重複內容。此代碼的結果完全不是。沒有改變。有小費嗎？

file_names = ['phone_numbers.txt'] 
    file_names.each do |file_name| 
     words_to_exclude = ["Employee Marked Urgency as: low", "Employee Marked Urgency as: high"] 
     text = File.read(file_name) 
     lines = text.split("\n") 
     new_contents = lines.uniq.reject do |word| 
     words_to_exclude.include? word 
     end.join("\n") 
     File.open(file_name, "w") { |file| file.puts new_contents } 
    end 

Answer 1

我不知道我的理解是正確的，但使用Array#uniq與塊應該做的伎倆：

require 'digest/sha1' # to generate uniqs 

file_names = ['phone_numbers.txt'] 
words_to_exclude = ["Employee Marked Urgency as: low", 
        "Employee Marked Urgency as: high"] 

file_names.each do |file_name| 
    res = File.readlines(file_name).each_with_index.uniq do |s, idx| 
    words_to_exclude.include?(s) ? 
     Digest::SHA1.hexdigest(idx.to_s) : s 
    end.join("\n") 
    File.write(file_name, res) 
end 

這是怎麼回事：如果我們從我們的名單中遇到的單詞，我們生成無論如何，一個uniq足夠的字符串是通過的;否則我們使用原始字符串進行比較。