如何通過extjs的store.sync（）方法捕獲數據發送

我正在extjs + Yii中工作。我的客戶端功能在yii中設置，服務器端功能在extjs中。在extjs控制器中我編寫了代碼發送動態生成存儲，設置其代理並使用sync（）方法存儲。如何通過extjs的store.sync（）方法捕獲數據發送

review:function() 
    { var reviewQuestionStore=Ext.create('Balaee.store.qb.QbqnsStore'); 
     proxy=reviewQuestionStore.getProxy(); 
     Ext.apply(proxy.api,{ 
      read:'http://127.0.0.1/s_balaee/Balaee/index.php/QuestionBank/Qbpaper/ReviewQuestionPaper', 
      create:'http://127.0.0.1/s_balaee/Balaee/index.php/QuestionBank/Qbpaper/ReviewQuestionPaper', 
     }); 
     Ext.apply(proxy.writer,{ 
      type:'json', 
      root:'records' 
     }); 

     Ext.apply(proxy.reader,{ 
      type:'json', 
      root:'questions' 
     }); 
     var getdata=this.getLocalvalue(); 
      UserId=getdata.data.userId; 

     //Using sync method 
     var check =Ext.create('Balaee.model.qb.QbqnsModel',{ 
        questionPaperNo:Paperno, 
        userId: UserId, 
       }); 
     reviewQuestionStore.add(check); 
     reviewQuestionStore.sync(); 
}

所以它的工作是正確的。而其發送JSON格式的數據原樣

{"records":{"userId":"5","firstName":"abc","middleName":"","lastName":"","languageId":"","primaryEmail":"[email protected]","birthDate":"","password":"","securityQuestionId":"","securityQuestionAnswer":"","isMale":"","creationTime":"","ipAddress":"","confirmationCode":"","userStatusId":"","question":"","id":null}}

現在，我要趕在警予控制器功能這個數據。我曾試圖原樣

$postData = json_decode(file_get_contents("php://input"), true); 
     $clientData = $postData['records'];

和訪問我使用$ clientData [「的firstName」]字段。但它不是working.So如何捕捉Yii中的數據是通過ExtJS的的商店同步（）方法來發送。

來源

2013-03-15 user1722857

使用標準的Yii的Json decode.It將創建數組，你

$data= CJSON::decode(file_get_contents("php://input"));

來源

2013-03-15 06:25:41

感謝名單先生......它的工作原理... – user1722857 2013-03-15 09:32:12

@ user1722857歡迎您 – 2013-03-15 10:36:09

如何通過extjs的store.sync（）方法捕獲數據發送

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